3) What is the probability that a resident owns a house but not a car? Check Show answer

Algebra and Trigonometry (MindTap Course List)
4th Edition
ISBN:9781305071742
Author:James Stewart, Lothar Redlin, Saleem Watson
Publisher:James Stewart, Lothar Redlin, Saleem Watson
Chapter14: Counting And Probability
Section14.3: Binomial Probability
Problem 32E
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Hi.  I need assistance with question #3.  I am not sure how to divide 46 with the information provided.    

Addition rule and complements
ACTIVITY
In a certain city, 46% of residents own a house, 67%% of residents own a car, and 21% of residents own both a house and a car.
Let A be the event that a randomly selected resident from the city owns a house and B be the event that a randomly selected
resident from the city owns a car.
1) What is the probability that a resident owns a house, a car, or both?
92
Correct
0.92
Check
Show answer
The addition rule is used to find P(AUB).
P(AU B) = P(A) P(B)- P(An B)
-0.46 + 0.67-0.21
0.92
2) What is the probability that a resident owns neither a house nor a car?
Correct
0.08
0.08
Check
Show answer
The event that a residentowns.neither a house nor a car
s AUB.The complement rule is used to find
P(AU B).
P(AUB)
=1-0.92
=0.08
P(AU B)= 1
-
%3D
3) What is the probability that a resident owns a house but not a car?
Incorrect
The event A can be divided into two mutually exclusive
events, the event that a resident owns a house and a car,
and the event that a resident owns a house but not a car.
Check
Show answer
Feedback?
Provide feedback
How was this section? I6 QI
Transcribed Image Text:Addition rule and complements ACTIVITY In a certain city, 46% of residents own a house, 67%% of residents own a car, and 21% of residents own both a house and a car. Let A be the event that a randomly selected resident from the city owns a house and B be the event that a randomly selected resident from the city owns a car. 1) What is the probability that a resident owns a house, a car, or both? 92 Correct 0.92 Check Show answer The addition rule is used to find P(AUB). P(AU B) = P(A) P(B)- P(An B) -0.46 + 0.67-0.21 0.92 2) What is the probability that a resident owns neither a house nor a car? Correct 0.08 0.08 Check Show answer The event that a residentowns.neither a house nor a car s AUB.The complement rule is used to find P(AU B). P(AUB) =1-0.92 =0.08 P(AU B)= 1 - %3D 3) What is the probability that a resident owns a house but not a car? Incorrect The event A can be divided into two mutually exclusive events, the event that a resident owns a house and a car, and the event that a resident owns a house but not a car. Check Show answer Feedback? Provide feedback How was this section? I6 QI
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