HomeworkIn 1-8, simplify the given expressions:3.V1601.V144V482.6.3723V32x4.5.8.V12xy2z77.000T

1. 144= 122= 1222=121=12Hence 144 =122. 48= 12×4 =2×2×3×4=2×2×3×22 =21+1+2×3=24×3=223= 43Hence 48…

Answered: 3. 2. 5. Homework In 1-8, simplify the…

Elementary Algebra

17th Edition

ISBN:9780998625713

Author:Lynn Marecek, MaryAnne Anthony-Smith

Publisher:Lynn Marecek, MaryAnne Anthony-Smith

Chapter1: Foundations

Section1.3: Add And Subtract Integers

Problem 1.85TI: Simplify: (a) 2113 and 21+(13) (b) 117 and 11+(7).

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Related questions

Question

Homework
In 1-8, simplify the given expressions:
3.
V160
1.
V144
V48
2.
6.
372
3V32x
4.
5.
8.
V12xy2z7
7.
000T

Expert Solution

Step 1

$1 . \sqrt{144} = \sqrt{12^{2}} = 12^{\frac{2}{2}} = 12^{1} = 12 H e n c e \sqrt{144} = 12 2 . \sqrt{48} = \sqrt{12 \times 4} = \sqrt{2 \times 2 \times 3 \times 4} = \sqrt{2 \times 2 \times 3 \times 2^{2}} = \sqrt{2^{1 + 1 + 2} \times 3} = \sqrt{2^{4} \times 3} = 2^{2} \sqrt{3} = 4 \sqrt{3} H e n c e \sqrt{48} = 4 \sqrt{3} 3 . \sqrt{160} = \sqrt{16 \times 10} = \sqrt{4^{2} \times 2 \times 5} = \sqrt{{(2^{2})}^{2} \times 2 \times 5} = \sqrt{2^{4} \times 2 \times 5} = 2^{2} \sqrt{2 \times 5} = 4 \sqrt{10} H e n c e \sqrt{160} = 4 \sqrt{10} 4 . 3 \sqrt{72} = 3 \sqrt{9 \times 8} = 3 \sqrt{3^{2} \times 2^{3}} = 3 \times 3 \sqrt{2^{2} \times 2} = 9 \times 2 \sqrt{2} = 18 \sqrt{2} H e n c e 3 \sqrt{72} = 18 \sqrt{2}$