3. A coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained. a. Volume of Bucket = 0.0094m³ b. Weight of empty bucket = 8,391 g c. Weight of bucket filled with dry rodded coarse aggregate = 25,355 g %3D %3D Calculate the dry-rodded unit weight. 4. Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained. a. Volume of Bucket = 0.0142m³ %3D b. Weight of empty bucket = 9,207 g c. Weight of bucket filled with dry rodded coarse aggregate: i. Trial 1= 34,745 g ii. Trial 2 = 34,0o65 g iii. Trial 3 = 35,743 g %3D Calculate the average dry-rodded unit weight

3. A coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained. a. Volume of Bucket = 0.0094m³ b. Weight of empty bucket = 8,391 g c. Weight of bucket filled with dry rodded coarse aggregate = 25,355 g %3D %3D Calculate the dry-rodded unit weight. 4. Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained. a. Volume of Bucket = 0.0142m³ %3D b. Weight of empty bucket = 9,207 g c. Weight of bucket filled with dry rodded coarse aggregate: i. Trial 1= 34,745 g ii. Trial 2 = 34,0o65 g iii. Trial 3 = 35,743 g %3D Calculate the average dry-rodded unit weight

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Similar questions

An aggregate sample has a compacted dry unit weight of 1615 kg/m3 and a dry specific gravity of 2.15 If this aggregate is placed in a container and compacted with the same procedure used in the determination of compacted unit weight, what will be the amount of pores, in percent of the container volume, between the aggregate particles? (density of water = 1000 kg/m3)
Void Content—Calculate the void content in the aggregate using the bulk densitydetermined by either the rodding, jigging or shoveling procedure, as follows:
Note: For computational purposes, provide virtual Data for the following term and compute for the Bulk Density and percent voids. For coarse aggregate: Volume of bucket Weight of empty bucket Weight of bucket filled with dry fine aggregate 2.68 Bulk Specific gravity of fine aggregate Bulk Unit Weight % Voids (make up computation, make your own data)
A sample of dry, coarse-grained material was shaken through a nest of sieves, and the following results were obtained. Determine the following: Sieve-analysis parameters: 1. Effective size, mm. 2. Average size, mm. 3. Coefficient of uniformity. 4. Coefficient of curvature. 5. Sorting coefficient.
Note: For computational purposes, provide virtual Data for the following term and compute for the Bulk Density and percent voids. For fine aggregate: Volume of bucket Weight of empty bucket Weight of bucket filled with dry fine aggregate 2.25 Bulk Specific gravity of fine aggregate Bulk Unit Weight % Voids (make up computation, make your own data)
Referring to the aggregate gradations A, B, and C in Figure , answer the following questions:a. What is the maximum size of each gradation?b. What is the nominal maximum size of each gradation?c. Classify each gradation as dense, open, or gap indicating the reason for each classification.
Determine Admixtures in ml/m3 Fine aggregate requirements (dry), in kg/m3 Net Water Content, in kg/m3
Table shows the grain size distributions of aggregates A, and B. Answer the following questions and show all calculations: What are the maximum sizes of aggregates A and B?
Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket =14L Weight of empty bucket = 9.21kg Weight of bucket filled with dry rodded coarse aggregate: Trial 1 =34,75 kg Trial 2 =34.06 kg Trial 3 =35.74 kg a. Calculate the average dry-rodded unit weight b.If the bulk dry specific gravity of the aggregate is 2.620, calculate the percent voids between aggregate particles for each trial.
Show complete solution. Coarse aggregate is placed in a rigid bucket and rodded with a tamping rod to determine its unit weight. The following data are obtained: Volume of bucket = 9.3 Liters Mass of empty bucket = 9 kg Mass of bucket filled with dry-rodded coarse aggregate: Trial 1 = 30.25 kg Trial 2 = 29.76 kg Trial 3 = 31.12 kg a. Calculate the individual dry-rodded unit weight for each trial and the average dry-rodded unit weight of all trials. b. If the bulk dry specific gravity of the aggregate is 2.65, calculate the percent voids between aggregates particles for each trial and the average percent voids of all trials.
Sieve analysis test for fine aggregates was performed on a sample of fine aggregates and produced the following results: a. Calculate the percent passing through each sieve.b. Plot the percent finer in a semi-log gradation chart.c. What is the maximum aggregate size of the sample?d. What is the nominal maximum aggregate size of the sample?e. What is the fineness modulus? Is it in typical range?
In the picture is a distribution graph of the sphericity of a sample of aggregate materials. The test was done using the Aggregate Imaging System (AIMS) that evaluates the shape characteristics of aggregates. What does the graph and quantitative results tell us about the representative sample?