3. A mass of 10 kNs2/m is suspended constant is 640 kN/m. The mass is initially released from a point 0.1 m below the equilibrium position (i.e., the origin of coordinate) with a downward velocity of 2.0 m/s. Assume no energy loss during the vibration (i.e., damping is ignored). (a) What is the natural circular frequency of the system? What is the natural period? (2) (b) Solve the differential equation using initial conditions. (c) Find the times at which the mass return to the equilibrium position. (3 Mass m X

Elements Of Electromagnetics
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FA(5:30PM)
3. A mass of 10 kNs2/m is suspended from a spring whose spring
constant is 640 kN/m. The mass is initially released from a point 0.1
m below the equilibrium position (i.e., the origin of coordinate)
with a downward velocity of 2.0 m/s. Assume no energy loss during
the vibration (i.e., damping is ignored).
(a) What is the natural circular frequency of the system? What is the
natural period? (2)
(b) Solve the differential equation using initial conditions.
(c) Find the times at which the mass return to the equilibrium
position. (3
Student ID:
Name:
or FB(1:00PM)
Mass m
JA
O
Transcribed Image Text:FA(5:30PM) 3. A mass of 10 kNs2/m is suspended from a spring whose spring constant is 640 kN/m. The mass is initially released from a point 0.1 m below the equilibrium position (i.e., the origin of coordinate) with a downward velocity of 2.0 m/s. Assume no energy loss during the vibration (i.e., damping is ignored). (a) What is the natural circular frequency of the system? What is the natural period? (2) (b) Solve the differential equation using initial conditions. (c) Find the times at which the mass return to the equilibrium position. (3 Student ID: Name: or FB(1:00PM) Mass m JA O
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