Number 3 Name: nttPeriod:Date:m:mnssCircular Motion Math WorksheetFormulas: T= 1/f|Fe = (mV2)/ r(N)Fe = m aef 1/T V= (2rr) / T a =V² /r(e)(N)1.A 0.5 kg ball moves in a circle that is 0.4 m in radius at a speed of 4.0 m/s. Calculate its centripetalacceleration.Givens/Unknown:mc 0.5KgEquation:Substitution:Solve:(hon/s)to mlsV= 4.0mls0.4m2.Calculate the centripetal force on the ball in question #1.Givens/Unknown:Equation:Substitution:Solve:3.A toy cart at the end of a string 0.70 m long moves in a circle on a table. The cart has a mass of 2.0 kgand the string has a breaking strength of 40. N. FC(A) Calculate the acceleration the toy cart as it moves in a circle.Givens/Unknown:m= 2.0 K2°c= Zom/s- JarEquation:Substitution:Solve:4oN m/sr=. 70 mFc= 4on(B) Calculate the maximum speed the cart can attain without breaking the string.Givens/Unknown:Equation:Substitution:Solve:4.(A) Calculate its linear speed at its tip in meters per second.Equation:(2T))rGivens/Unknown:Substitution:Solve:(=0.55(? T) 0.5V-T-360053600(B) Calculate the centripetal acceleration of the tip of the hand.Equation:Givens/Unknown:Substitution:Solve:cycboA phonograph record 30.0 cm in diameter rotates 33.5 times per minute. 20-cm 30,5-(A) What is its frequency?Givens/Unknown:5.Equation:Substitution:Solve:Time(B) What is its period?Givens/Unknown:Equation:Substitution:Solve:

Name: Number 3 Name: nttPeriod:Date:m:mnssCircular Motion Math WorksheetForm
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Description: Number 3 Name: nttPeriod:Date:m:mnssCircular Motion Math WorksheetFormulas: T= 1/f|Fe = (mV2)/ r(N)Fe = m aef 1/T V= (2rr) / T a =V² /r(e)(N)1.A 0.5 kg ball moves in a circle that is 0.4 m in radius at a speed of 4.0 m/s. Calculate its centripetalacc

Length of string = 0.7m Mass of cart = 2kg Breaking strength =40N

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Physics

3. A toy cart at the end of a string 0.70 m long moves in a circle on a table. The cart has a mass of 2.0 kg and the string has a breaking strength of 40. N. Fe (A) Calculate the acceleration the toy cart as it moves in a circle. Givens/Unknown: m= 2.0 K) r=.70 m Equation: Substitution: Solve: 4oN m/s ac (B) Calculate the maximum speed the cart can attain without breaking the string. Givens/Unknown: Equation: Substitution: Solve:

3. A toy cart at the end of a string 0.70 m long moves in a circle on a table. The cart has a mass of 2.0 kg and the string has a breaking strength of 40. N. Fe (A) Calculate the acceleration the toy cart as it moves in a circle. Givens/Unknown: m= 2.0 K) r=.70 m Equation: Substitution: Solve: 4oN m/s ac (B) Calculate the maximum speed the cart can attain without breaking the string. Givens/Unknown: Equation: Substitution: Solve:

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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