3. Apply the Chain Rule and explain the differences among the following four ex- amples from the point of view of differentiation. Compute explicitly each one of the given derivatives: (cos(5z)) = (cos(=*)) = cos (z) = and (cos(sin(5z))) =

College Algebra (MindTap Course List)
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Author:R. David Gustafson, Jeff Hughes
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Chapter3: Functions
Section3.3: More On Functions; Piecewise-defined Functions
Problem 99E: Determine if the statemment is true or false. If the statement is false, then correct it and make it...
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Question 3
2. Now, as discussed in class, the absolute value function is formally defined as
z, if a 20
-{-3,if z<0
S(z) = |z| =
a) Sketch the graph of this function.
b) What is the only critical point of this function? Explain.
c) Would the critical point change in any way if we would consider g(x) = 2|x| instead
of f(x) = |x|? Explain why or why not.
3
3. Apply the Chain Rule and explain the differences among the following four ex-
amples from the point of view of differentiation. Compute explicitly each one of the
given derivatives:
(cos(5z)) =
Ccon(z")) =
dr
cos"(z) =
and
d
(cos(sin(5æ))) =
dz
4. Now, as explained in class, recall that some functions are defined implicitly by a
relation between z and y such as r² + y² = 4. In such cases, differentiating with respect
to a both sides helps us compute y'= 4. We should be careful, however, with the Chain
Rule that needs to be applied in the way. That is, if y is assumed to be a function of æ,
then
(y²)' = 2y(y/')
(e")' = (e")y/
and so on.
This process is called impne amerenciationr
Transcribed Image Text:2. Now, as discussed in class, the absolute value function is formally defined as z, if a 20 -{-3,if z<0 S(z) = |z| = a) Sketch the graph of this function. b) What is the only critical point of this function? Explain. c) Would the critical point change in any way if we would consider g(x) = 2|x| instead of f(x) = |x|? Explain why or why not. 3 3. Apply the Chain Rule and explain the differences among the following four ex- amples from the point of view of differentiation. Compute explicitly each one of the given derivatives: (cos(5z)) = Ccon(z")) = dr cos"(z) = and d (cos(sin(5æ))) = dz 4. Now, as explained in class, recall that some functions are defined implicitly by a relation between z and y such as r² + y² = 4. In such cases, differentiating with respect to a both sides helps us compute y'= 4. We should be careful, however, with the Chain Rule that needs to be applied in the way. That is, if y is assumed to be a function of æ, then (y²)' = 2y(y/') (e")' = (e")y/ and so on. This process is called impne amerenciationr
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