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Asked Oct 8, 2019
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3. Both parents are heterozygous dominant for a chin fissure gene
Mom's genotype
Dad's genotype:
A. Probability that child will have
a chin fissure?
B. Probability that child will be
homozygous dominant for a chin
fissure?
C. Probability that child will be
heterozygous dominant for a chin
fissure?
D. Probability that child will be
homozygous recessive for a
smooth chin?
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3. Both parents are heterozygous dominant for a chin fissure gene Mom's genotype Dad's genotype: A. Probability that child will have a chin fissure? B. Probability that child will be homozygous dominant for a chin fissure? C. Probability that child will be heterozygous dominant for a chin fissure? D. Probability that child will be homozygous recessive for a smooth chin?

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Expert Answer

Step 1

The allele combination of a gene present in an organism determines the genotype and phenotype. The genotype is the specific allele combination of a gene and the physical manifestation of the genotype is known as phenotype. An organism with two copies of same dominant allele is homozygous dominant and the organism with two copies of same recessive alleles is homozygous recessive. Heterozygous genotype consists of two different alleles of a gene.

Step 2
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It is given that both the parents are heterozygous dominant for a chin fissure gene. Thus the genotype of father is Ff and the genotype of mother is Ff. Where F is the dominant allele and f is the recessive allele. The probability can be estimated by the punnett square Male/ Female f FF Ff f Ff ff From the punnett square, it is clear that 25% of children are homozygous dominant (FF), 50% are heterozygous dominant (Ff) and 25% are homozygous recessive (ff)

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