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- Consider the series RLC circuit of Problem 2.7 and calculate the complex power absorbed by each of the R, L, and C elements, as well as the complex power absorbed by the total load. Draw the resultant power tna ngle. Check whether the complex power delivered by the source equals the total complex power absorbed by the load.Given the complex numbers A1=630 and A2=4+j5, (a) convert A1 to rectangular form: (b) convert A2 to polar and exponential form: (c) calculate A3=(A1+A2), giving your answer in polar form: (d) calculate A4=A1A2, giving your answer in rectangular form: (e) calculate A5=A1/(A2*) giving your answer in exponential form.Question 777 All part work u ?? Full explain this question very fast solution sent me I give you thum all part work u Fast ...
- 1st five subparts please also show circuitThe actual impedance of a system is 300 Ω. The base kVA is 300 kVA, and the base voltage is 11 kV. What is the actual impedance with 400 kVA and 38 kV as base values? a. 300 b. 33.52 c. 0.744 d. 0.083A series RL circuit in which R=5 ohms and L=20 mH has an applied voltage e=100+50sinwt+25sin3wt with w=500 radians per sec. Determine the power dissipated in the resistor of the circuit.