3. Explain the difference in reactivity for the two sets of reactions below: HO HO HBr Br До-то HBr No Reaction Хо-тв Ts=Tosylate NaN, Ny Fast NaN, Very slow ・ N
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- Which compound is not a possible product in the reaction below ( F2 is in excess F2and UV light the catalyst).CHA + F2 -->O CFAO CHFaO CHF-O CH2F2O CHaFConsider the reactions shown below. For each reaction state if it would favor S N 1 or S N 2pathway and give the major product of the reaction.Arrange the alkyl halides in order of increasing reactivity in an SN2 reaction with KI in acetone (least first). I, IV, III, II II, III, I, IV IV, I, III, II III, II, IV, I
- [IV1] Instructions: Follow the flow of electrons indicated by the curved arrows in each of the following reactions, and predict the products that result: (refer to the photo below)Identify the reagents needed to come up with the given compounds. Pls Separate the reagents with a comma and a space. (ex. HNO3, H2SO4). For a multi-step reaction, separate the reagents with a semi-colon. (ex. HNO3, H2SO4; CH3Cl, AlCl3) There should be 9 reagents1) The Predict the product(s). 2)Label any kinetic/thermodynamic product(s). 3)Give reason towards the selection of kinetic product(s).
- 6. For each of the following reactions: a) say what is the expected Mechanism sn1 or sn2 and say why. b) For some of the reactions say if the product is optically active and say why. c) For some of the rxns say if their kinetics are unimolecular (Uni) or bimolecular (Bi) and explain MechanisOrgonic Chmeistry II: 2,4,6-Trinitrotoluene (TNT) is synthesized by trinitrating toluene. The first nitration proceeds much faster than the second two. Briefly explain.Arrange the nucleophiles in order of increasing reactivity (least first). III, II, I, IV IV, III, I, II IV, I, II, III III, I, IV, II
- Why we need step 3 before step 4? a. Because the nitro group increases the electrophilicity at the ortho positions which is where the bromine is added. b. Because the amine group is a strong ortho, para director which is what controls the regiochemical outcome of this bromination. c. Step 4 is unessesary. The symmetry of compound 3 allows for the bromination to be regioselective and give compound 5. 5. There will be a mixture of products because there is no selectivity for a major product.Choose the best reagents from the list provided below for carrying out the following conversion. Match the reagent with the step number. HCl (aq), Zn(Hg) Br2, FeBr3 Na/NH3, -33 degrees C NBS, light KMnO4, H3O+ Mg metal, ether KOH, EtOH, heat(b) Predict the suitable solvent (H2O or CH3COCH3) to increase the reaction of bromopropane(CH3CH2CH2Br) with sodium hydroxide (NaOH). Two reactions are shown below: