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- Calculate the mass percent of the ascorbic acid in the same show full solution Situation: The pounded Vitamin C tablet was half into two below are the calculated data in the experiment. Each of the half are transfered in a 250ml erlen meyer flask and added 75ml of deionized water for the vitamin C to dissolve. Then it was prepared for titration where the burette was filled with 0.09794M standardize NaOH solution then a total of with 3 drops 2% phenolphthalein indicator was added to each erlen meyer flask l, swrill it and begin the titration. below are the following data gathered: Vitamins used: Nature Made vitamin C 500mg tablet Trial 1 Mass: 0.3108g of Vitamin C tablet Initial volume: 1.6mL Final volume: 15.4mL Trial 2 Mass: 0.3349g Initial volume: 15.4 mL Final volume: 30.2 mL1.) Use the line of best ! Tables: Data Port 1. Synthesis of Asprin \table[[Mass of galicylic Acid used 2.024gt to calculate the concentration of the salicylic Acid in your asprin saple solution (in 50.0 ml volumettic flask) 2.) Use M1V1 = M2V2 to determine the concentration of salicylic acid in your 100.0 mL solution before dilutuon to 50.0mL for analysis. 3.) Determine the mass of salicylic acid present in the 4g sample of synthesized asprin tht was dissolved in the 100.0ml, volumetric flask 4.) Determine the percent of salicylic acid and percent asprin in the 4g sample of synthesized asprin7 5.) Calculate the theoretical yelld of asprin for your synthesis reaction. Assume that the salicylic acid used in the salicylic used in the synthesis reaction is the limiting reactant. 6. Determine the percent yild of the asprin for your synthesis. For the 1st cacization i got 1.340x10^-4 M C7H603 For the 2nd calculation i got M167x10^-5 Please check my calculations and explain the remainingA 500.00 mg vitamin C (MW176.12g/mol) tablet was ground, acidified, and dissolved in H2O to make a 250.0 mL solution. A 50.00 mL aliquot containing vitamin C, KI and starch was analyzed and titrated with 12.31 mL of 0.01042 M KIO3. What is the % (w/w) vitamin C in the tablet? KIO3 + 5 KI + 6 H+ = 3 I2 + 6 K+ + 3 H2O C6H8O6 + I2 = C6H6O6 + 2I- + 2H+ A 67.77 % B 33.89 % C 22.59 % D 3.39 %