3. In Part C, you prepare four solutions (starting concentrations are given blow) in test tubes and you will measure the Absorbance after the solutions have reached equilibrium. Shown below is an example of just ONE solution, with absorbance data shown as well. Using this data and the standard curve from question 2 on the previous page, calculate Kf. SHOW ALL WORK BELOW! Starting Concentrations Test Tube 0.00200 M Fe(NO3)3 [mL] 0.0020 M KSCN [mL] H20 [mL] 1 3.0 2.0 5.0 Absorbance Data [FESCN2"] at equilibrium Test Tube Absorbance at Amax Kf 1 0.118 2.88 x 10-4 M

Principles of Instrumental Analysis
7th Edition
ISBN:9781305577213
Author:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Chapter24: Coulometry
Section: Chapter Questions
Problem 24.12QAP
icon
Related questions
Question

Correct the fol

3. In Part C, you prepare four solutions (starting concentrations are given blow) in test tubes and
you will measure the Absorbance after the solutions have reached equilibrium. Shown below is
an example of just ONE solution, with absorbance data shown as well. Using this data and the
standard curve from question 2 on the previous page, calculate Kf.
SHOW ALL WORK BELOW!
Starting Concentrations
Test Tube
0.00200 M Fe(NO3)3 [mL] 0.0020 M KSCN [mL]
H20 [mL]
1
3.0
2.0
5.0
Absorbance Data
(FESCN2*] at
equilibrium
Test Tube
Absorbance at Amax
Kf
1
0.118
2.88 x 10-4 M
Given absorbance: y = 0.118
y - 0.0483
X =:
2417.5
0.118 – 0.0483
2417.5
x = 2.883 x 10$ M
(FESCN2*] = 2.88 x 10$ M
MFex VFe
0.002 x 3
(Fe**) =
0.006 M
Total Volume
MSCN X V SCN
10
0.002 x 2
(SCN'] =
= 0.0004 M
%3D
Total Volume
10
ICE Table:
Fe3+
SCN
FESCN2+
0.006
0.0004
-X
-X
+x
0.006 -x
0.004 - x
[FESCN2+]
Kf =
[Fe3+][SCN-]
(0.006 – x)(0.004 - x)
0.118 = 2417.5 + 0.0483
2417.5x = 0.334 - 0.0483 = 0.0697
0.0697
X =
= 2.88 x 10-5 M
2417.5
At equilibrium,
(FESCN2*] = 2.88 x 10S M
(Fe3*] = 0.0060 - x = 0.0060 –- 2.88 x 105 = 0.0059712
[SCN'] = 0.0040 – x = 0.0040 - 2.88 x 10S = 0.0039712
%3D
not sure what
wernt wrong -.
2.88 x 10-5
Kf =
(0.0059712 x 0.0039712)
Kf = 121
Transcribed Image Text:3. In Part C, you prepare four solutions (starting concentrations are given blow) in test tubes and you will measure the Absorbance after the solutions have reached equilibrium. Shown below is an example of just ONE solution, with absorbance data shown as well. Using this data and the standard curve from question 2 on the previous page, calculate Kf. SHOW ALL WORK BELOW! Starting Concentrations Test Tube 0.00200 M Fe(NO3)3 [mL] 0.0020 M KSCN [mL] H20 [mL] 1 3.0 2.0 5.0 Absorbance Data (FESCN2*] at equilibrium Test Tube Absorbance at Amax Kf 1 0.118 2.88 x 10-4 M Given absorbance: y = 0.118 y - 0.0483 X =: 2417.5 0.118 – 0.0483 2417.5 x = 2.883 x 10$ M (FESCN2*] = 2.88 x 10$ M MFex VFe 0.002 x 3 (Fe**) = 0.006 M Total Volume MSCN X V SCN 10 0.002 x 2 (SCN'] = = 0.0004 M %3D Total Volume 10 ICE Table: Fe3+ SCN FESCN2+ 0.006 0.0004 -X -X +x 0.006 -x 0.004 - x [FESCN2+] Kf = [Fe3+][SCN-] (0.006 – x)(0.004 - x) 0.118 = 2417.5 + 0.0483 2417.5x = 0.334 - 0.0483 = 0.0697 0.0697 X = = 2.88 x 10-5 M 2417.5 At equilibrium, (FESCN2*] = 2.88 x 10S M (Fe3*] = 0.0060 - x = 0.0060 –- 2.88 x 105 = 0.0059712 [SCN'] = 0.0040 – x = 0.0040 - 2.88 x 10S = 0.0039712 %3D not sure what wernt wrong -. 2.88 x 10-5 Kf = (0.0059712 x 0.0039712) Kf = 121
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 2 steps

Blurred answer
Knowledge Booster
Electroanalytical Techniques
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Principles of Instrumental Analysis
Principles of Instrumental Analysis
Chemistry
ISBN:
9781305577213
Author:
Douglas A. Skoog, F. James Holler, Stanley R. Crouch
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781305957404
Author:
Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:
Cengage Learning
Chemistry
Chemistry
Chemistry
ISBN:
9781133611097
Author:
Steven S. Zumdahl
Publisher:
Cengage Learning
Chemistry: An Atoms First Approach
Chemistry: An Atoms First Approach
Chemistry
ISBN:
9781305079243
Author:
Steven S. Zumdahl, Susan A. Zumdahl
Publisher:
Cengage Learning
Fundamentals Of Analytical Chemistry
Fundamentals Of Analytical Chemistry
Chemistry
ISBN:
9781285640686
Author:
Skoog
Publisher:
Cengage
Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
Chemistry
ISBN:
9781305079373
Author:
William L. Masterton, Cecile N. Hurley
Publisher:
Cengage Learning