3. Matrices and vectors a. Compute the following [2 marks] -5x² + 7y² + 2z² + 2xy + 8xz -6yz -5x² + 7y² + 2z² + 2xy - 6xz+8yz 5x² + 7y² + 2z² + 2xy +6xz-8yz • 5x² + 7y² + 2z² - 2xy - 6xz+8yz ¹ (¹ 2²¹) ²² b. What's the inverse of -5 1 -3 •(90)- 17 4 -3 4 2 (x y z) ? You should use the definition of inverse and check the conditions for each matrix in turn. [2 marks] 2 (44) =? -1/3 1/3) (12) (-1/3 2/3)
3. Matrices and vectors a. Compute the following [2 marks] -5x² + 7y² + 2z² + 2xy + 8xz -6yz -5x² + 7y² + 2z² + 2xy - 6xz+8yz 5x² + 7y² + 2z² + 2xy +6xz-8yz • 5x² + 7y² + 2z² - 2xy - 6xz+8yz ¹ (¹ 2²¹) ²² b. What's the inverse of -5 1 -3 •(90)- 17 4 -3 4 2 (x y z) ? You should use the definition of inverse and check the conditions for each matrix in turn. [2 marks] 2 (44) =? -1/3 1/3) (12) (-1/3 2/3)
College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter6: Linear Systems
Section6.3: Matrix Algebra
Problem 78E
Related questions
Question
![3. Matrices and vectors
a. Compute the following [2 marks]
-5x² + 7y² + 2x² + 2xy +8xz - 6yz
• -5x² + 7y² + 2z² + 2xy - 6xz+8yz
·
5x² + 7y² + 2z² + 2xy +6xz-8yz
• 5x² + 7y² + 2z² - 2xy - 6xz+8yz
b. What's the inverse of
(²
(x y z)
-5 1 -3
G+90-
1 7 4
-3 4 2
=?
? You should use the definition of inverse and check the conditions for each matrix in turn. [2 marks]
2
2/3 1/31
-1/3 1/3
(12)
(-1/3 2/3)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F132d1f06-8382-4e3d-a03b-0a0ac6c03e09%2Fc756ad76-fd31-42fd-a4fb-281086562047%2Fp8kfpo_processed.png&w=3840&q=75)
Transcribed Image Text:3. Matrices and vectors
a. Compute the following [2 marks]
-5x² + 7y² + 2x² + 2xy +8xz - 6yz
• -5x² + 7y² + 2z² + 2xy - 6xz+8yz
·
5x² + 7y² + 2z² + 2xy +6xz-8yz
• 5x² + 7y² + 2z² - 2xy - 6xz+8yz
b. What's the inverse of
(²
(x y z)
-5 1 -3
G+90-
1 7 4
-3 4 2
=?
? You should use the definition of inverse and check the conditions for each matrix in turn. [2 marks]
2
2/3 1/31
-1/3 1/3
(12)
(-1/3 2/3)
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