3. Quadrilateral LOVE is a kite in which LV=8 in and OE=20 in. What is the area of the kite? Given: Quadrilateral LIKE is a kite with LI TK and LE a KE. LE is twice LI. If its perimeter is 21 cm, how long LE? 3. a. Formula of Perimeter of Kite Substitution Perimeter of Kite 2S: + 2S2 21 2L1 + 2(2LI) 21 2S1 + 4LI 21 = 6LI LI = 3.5 cm LE = 7 cm Multiplication Property Combining like terms Dividing both sides by 6 LE is twice LI What is the area if one of the diagonats is 4 more than the other and IË + LK = 16 inches? TE + LK = 16 x+ x+4) = 16 2x+ 4 16 2x + 4 4 =16-4 b. Given Substitution Combining like terms Addition Property of Equality Subtraction Property Dividing both sides by 2 Formula of Area of Kite 2x = 12 x=6 Area of Kite= TE) (LK) Area of Kite 6(10) Area of Kite 30 inches2 Area of Kite = Substitution Substitution %3D Multiplication Property
3. Quadrilateral LOVE is a kite in which LV=8 in and OE=20 in. What is the area of the kite? Given: Quadrilateral LIKE is a kite with LI TK and LE a KE. LE is twice LI. If its perimeter is 21 cm, how long LE? 3. a. Formula of Perimeter of Kite Substitution Perimeter of Kite 2S: + 2S2 21 2L1 + 2(2LI) 21 2S1 + 4LI 21 = 6LI LI = 3.5 cm LE = 7 cm Multiplication Property Combining like terms Dividing both sides by 6 LE is twice LI What is the area if one of the diagonats is 4 more than the other and IË + LK = 16 inches? TE + LK = 16 x+ x+4) = 16 2x+ 4 16 2x + 4 4 =16-4 b. Given Substitution Combining like terms Addition Property of Equality Subtraction Property Dividing both sides by 2 Formula of Area of Kite 2x = 12 x=6 Area of Kite= TE) (LK) Area of Kite 6(10) Area of Kite 30 inches2 Area of Kite = Substitution Substitution %3D Multiplication Property
Elementary Geometry For College Students, 7e
7th Edition
ISBN:9781337614085
Author:Alexander, Daniel C.; Koeberlein, Geralyn M.
Publisher:Alexander, Daniel C.; Koeberlein, Geralyn M.
Chapter9: Surfaces And Solids
Section9.4: Polyhedrons And Spheres
Problem 23E: The surface of a soccer ball is composed of 12 regular pentagons and 20 regular hexagons. With each...
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