3. Table 2 shows the results of the standard proctor test Water content (%) Weight (kg) 14 Table 2. Proctor Test Results 1,45 1,71 1,87 1,88 16,5 18,5 20 21 22,5 If this test uses a sample print with a size of 943 cm^3, answer these question b. Determine the range of moisture content for 90% compaction in the field. 1,76 1,67

3. Table 2 shows the results of the standard proctor test Water content (%) Weight (kg) 14 Table 2. Proctor Test Results 1,45 1,71 1,87 1,88 16,5 18,5 20 21 22,5 If this test uses a sample print with a size of 943 cm^3, answer these question b. Determine the range of moisture content for 90% compaction in the field. 1,76 1,67

Fundamentals of Geotechnical Engineering (MindTap Course List)

5th Edition

ISBN:9781305635180

Author:Braja M. Das, Nagaratnam Sivakugan

Publisher:Braja M. Das, Nagaratnam Sivakugan

Chapter5: Soil Compaction

Section: Chapter Questions

Problem 5.2P

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the following data have been obtained in a standard laboratory proctor compaction test : Trial No. moisture content. % 1 9 2 3 4 6 11.9 14.6 15-8 19.0 21.6 weight of container and compacted soil 137.43 38.16 38-67 38-8439-06 38.76 (N) The container is 943 cm³ ih volume and its weight is 201 A-Determine the optimum moisture content and the maximum dry unit weight B-what is the dry uhit weight and water content at 95% standard compaction in the field ?
2. The resulting of the Standard Proctor Test is as follows: Vol. of Proctor Mold Wt. of wet soil in mold Moisture (cu.m) (kg) (%) 943.3 1.76 12 943.3 1.86 14 943.3 1.92 16 943.3 1.95 18 943.3 1.93 20 943.3 1.90 22 a. Determine the maximum dry unit weight of compaction b. Determine the optimum moisture content
The resulting of the Standard Proctor Test is as follows: Vol. of Proctor Mold (cu.m) Wt. of wet soil in mold (kg) Moisture (%) 943.3 1.76 12 943.3 1.86 14 943.3 1.92 16 943.3 1.95 18 943.3 1.93 20 943.3 1.90 22 a. Determine the maximum dry unit weight of compaction b. Determine the optimum moisture content
Afalling-head permeability test is performed on a fine-grained soil. The soil sample has a length of 120 mm and a cross-sectional area of 600 mm2. The water in the standpipe flowing into the soil is 0.60 m above the top of the sample at the start of the test. It falls 50 mm in 30 minutes. The standpipe has a cross-sectional area of 200 mm2. (a) Make a sketch of the described conditions. (b) What is the coefficient of permeability in millimeters per second? (c) What is the coefficient of permeability in feet per minute? (d) On the basis of the calculated value for khyd, what is the probable soil type?
b. Compute the plastic limit. C. Compute the natural water content. d. Compute the plasticity index. e. Compute the liquidity index. f. Compute the consistency index. PROBLEM NO. 4 From the table shows a summary of a liquid limit and plastic limit test. LIQUID LIMIT TEST Soil Wt. of wet Wt. of dry Water No. of Sample Soil (kg) Soil (kg) A. Content Blows 9.5 6.7 28 B 7.95 5.54 20 8.21 5.69 18 D. 12.85 8.83 13 PLASTIC LIMIT TEST Wt. of Dry Soil(kg) Soil Wt, of Wet Sample Soil(kg) 9.05 7.35 2 8.66 7.01 Natural Water Content Scil Wt. of Wt. of Sample Wet Soil Dry Soi! 1 9.69 7.0 9.47 6.86 a. Compute the liquid limit. b. Compute the plastic limit. C. Compute the natural water content. d. Compute the plasticity index. e. Compute the liquidity index GEOTECHNICAL ENGINEERING 1
The volume of the solids is 65cc. The wet weight of the soil is 198g having a saturation at 48% and the dried weight is 176g. Determine the following: a. Total volume of the sample, cc. b. Volume of the voids, cc. c. Air void ratio, %.
A standard Proctor Test has yielded the values shown below. Determine: (a) The maximum dry unit weight and its OMC at Volume of 1/30 cubic ft. (b) The moisture for 93% of maximum dry unit weight. range STANDARD PROCTOR TEST RESULTS TRIAL WEIGHT OF SOIL (Ibs.) MOISTURE (%) |8.24 3.26 4.15 1 10.20 4.67 12.30 4. 4.02 14.60 3.36 16.80 23
The results of a standard and a modified Proctor tests ate given in the table below. a) Generate a plot of dry unit weight as a function of water content including the zero air voids (ZAV) curve (note that the units are in cm³ and kg). b) Determine the maximum dry unit weight of compaction and the optimum moisture content. Show calculation on how to determine the maximum dry density and the optimum moisture content. STANDARD PROCTOR TEST DATA MODIFIED PROCTOR TEST DATA Volume of Mass of Wet Soil Water Content, Mass of wet soil Water Content, Mold (cm?) in the mold (kg) wC in the mold (kg) wC 1.68 0.099 1.83 0.059 1.71 0.106 1.89 0.066 1.77 0.121 1.95 0.081 1.83 0.138 2.00 0.098 943.3 1.86 0.151 2.03 0.111 1.88 0.174 2.05 0.134 1.87 0.194 2.04 0.154 1.85 0.212 2.00 0.172
5.5 The modified Proctor test (ASTM D 698, method C) was performed for a soil with G, = 2.70, and the results are as follows: Moist Weight in Mold, gf Water Content, % 6.5 3250 9.3 3826 12.6 4293 14.9 4362 17.2 4035 18.6 3685 (a) Plot the Ya versus w relation. (b) Determine Ya,max and wopt- (c) Calculate S and e at the maximum dry unit weight point. (d) What is Y, at Wopt? What is the range of water content if the relative compaction (R.C.) is required to be 95% of the modified Proctor Ya.max?
5.5 The modified Proctor test (ASTM D 698, method C) was performed for a soil with G, = 2.70, and the results are as follows: Moist Weight Content, % in Mold, gf Water 6.5 3250 9.3 3826 12.6 4293 14.9 4362 17.2 4035 18.6 3685 (a) Plot the Ya versus w relation. (b) Determine Ya,max and wopt- (c) Calculate S and e at the maximum dry unit weight point.
2) Using the following results: weight of dried pan and sand Is 1.0376 g. weight of pan and liquid sample is 4.6274 g. and weight of the pan and dried sample is 1.7321 g. What was the moisture content of the sample and what is the percent total solids?
A constant head permeability test is performed on soil that is 4 cm2, and 2.5cm long. The head difference applied during the test is 20 cm and 7 cm3 is collected over a time of 100 sec. Provide step by step solution. What is the permeability based on these test conditions and results.