3. The aluminum block has the rectangular cross-section and is subjected to an axial compressive force of 8 kips. The 1.5-in side changed its length to 1.50014 inches. Use E = 10 x 10³ ksi. Calculate the new length of the 2-inch side. Answer: Lnew = 2.00019 in

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter11: Columns
Section: Chapter Questions
Problem 11.5.12P: An aluminum box column with a square cross section is fixed at the base and free at the top (sec...
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3. The aluminum block has the rectangular cross-section and is subjected to an axial compressive force
of 8 kips. The 1.5-in side changed its length to 1.50014 inches. Use E = 10 x 10³ ksi. Calculate the new
length of the 2-inch side.
Answer: Lnew = 2.00019 in
1.5 in
2 in.
8 kip-
8 kip
3 in.
4. A solid cylinder of diameter D is subjected to an axial load P. Show that its change in diameter is 8D =
4Pv/лDE.
Transcribed Image Text:3. The aluminum block has the rectangular cross-section and is subjected to an axial compressive force of 8 kips. The 1.5-in side changed its length to 1.50014 inches. Use E = 10 x 10³ ksi. Calculate the new length of the 2-inch side. Answer: Lnew = 2.00019 in 1.5 in 2 in. 8 kip- 8 kip 3 in. 4. A solid cylinder of diameter D is subjected to an axial load P. Show that its change in diameter is 8D = 4Pv/лDE.
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