3. The batteries shown in the circuit below have negligibly small internal resistances. Find the current through (a) the 30.02 resistor; I 0.333 A (b) the 20.02 resistor; and I = 0.250 A (c) the 10.0 V battery. I = 0.583 A 10.0 V 30.0 Ω 20.0 5.00 V 4. A 1.50 µF capacitor is charging through a 12.02 resistor using a 10.0 V battery. What will be the current when the capacitor has acquired 1/4 of its maximum charge? I = 0.625A

Physics for Scientists and Engineers with Modern Physics
10th Edition
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Raymond A. Serway, John W. Jewett
Chapter27: Direct-current Circuits
Section: Chapter Questions
Problem 34AP: The circuit in Figure P27.34a consists of three resistors and one battery with no internal...
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3. The batteries shown in the circuit below have negligibly small internal resistances. Find the current through
(a) the 30.02 resistor; I
0.333 A
20.0 (b) the 20.02 resistor; and
I = 0.250 A
10.0 V
30.0
Ω
5.00 V
(c) the 10.0 V battery. I= 0.583 A
4. A 1.50 μF capacitor is charging through a 12.02 resistor using a 10.0 V battery. What will be the current when
the capacitor has acquired 1/4 of its maximum charge? I = 0.625A
Transcribed Image Text:3. The batteries shown in the circuit below have negligibly small internal resistances. Find the current through (a) the 30.02 resistor; I 0.333 A 20.0 (b) the 20.02 resistor; and I = 0.250 A 10.0 V 30.0 Ω 5.00 V (c) the 10.0 V battery. I= 0.583 A 4. A 1.50 μF capacitor is charging through a 12.02 resistor using a 10.0 V battery. What will be the current when the capacitor has acquired 1/4 of its maximum charge? I = 0.625A
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