#3. The contrabassoon is a wind instrument capable of sounding the lowest pitch in an orchestra. It is folded over several times to fit its impressive 18 ft length into a reasonable size instrument. a. If we model the instrument as an open-closed tube, what is its fundamental frequency? The sound speed inside is 350 m/s because the air is warmed by the players' breath. b. The actual fundamental frequency of the contrabassoon is 27.5 Hz, which should be different from your answer in part a. This means the model of the instrument as an open- closed tube is a bit too simple. But if you insist on using that model, what is the "effective length" of the instrument?

Physics for Scientists and Engineers, Technology Update (No access codes included)
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Chapter18: Superposition And Standing Waves
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Problem 18.11OQ: Suppose all six equal-length strings of an acoustic guitar are played without fingering, that is,...
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# 3. The contrabassoon is a wind instrument capable of sounding the lowest pitch in an
orchestra. It is folded over several times to fit its impressive 18 ft length into a reasonable size
instrument.
a. If we model the instrument as an open-closed tube, what is its fundamental frequency?
The sound speed inside is 350 m/s because the air is warmed by the players' breath.
b. The actual fundamental frequency of the contrabassoon is 27.5 Hz, which should be
different from your answer in part a. This means the model of the instrument as an open-
closed tube is a bit too simple. But if you insist on using that model, what is the "effective
length" of the instrument?
Transcribed Image Text:# 3. The contrabassoon is a wind instrument capable of sounding the lowest pitch in an orchestra. It is folded over several times to fit its impressive 18 ft length into a reasonable size instrument. a. If we model the instrument as an open-closed tube, what is its fundamental frequency? The sound speed inside is 350 m/s because the air is warmed by the players' breath. b. The actual fundamental frequency of the contrabassoon is 27.5 Hz, which should be different from your answer in part a. This means the model of the instrument as an open- closed tube is a bit too simple. But if you insist on using that model, what is the "effective length" of the instrument?
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