Number 3 thanks! Find the zeros of the following polynomials by using the following aids.Use the rational zero theorem, Descartes's rule of signs, and the theorem on bounds as aids in findingall real and imaginary roots to each equation.htt(h-)のでtz(h-)6+c(h-)X4,-3,-2 are1. x + 9x? + 26x + 24 = 0a. Good guesses:the roots Of ephob. # of positive roots:c. # of negative roots:d. # of imaginary roots:K+4) x 3+ 9x2+26x+24 (x2+5xt0 "" -ve" -3X 3e. upper boundf. lower bound+4x2there Is no bound5x²+20x+24 (x+4)(x?+5x+e)=ouince lim fA) eg. answers:xQしtzXg6.6x+242. 2x3-7x2 – 16= 0B The root of the equaionisa. Good guesses:Q-01-zメL-×tThere are no negatNeb. # of positive roots:c. # of negative roots:d. # of imaginary roots:s4009-の1-×hとメhてメナ。メてD. theOこの1-メーローメhtzメ+をメtbound3(htメtz×2) (h-X)the tanation is -e. upperf. lower boundimaginary rootofhりeg. answers:Lhこxzvて(1E- こX3. x + 3x³ + 2x = 0a. Good guesses:b. # of positive roots:c. # of negative roots:d. # of imaginary roots:e. upper boundf. lower boundg. answers:-ニzX!4こX

Answered: Image /qna-images/answer/99eeb7ee-c39e-465f-8a76-eed4c57203dd.jpg

Answered: 3. x + 3x + 2x = 0 %3D a. Good guesses:…

3. x + 3x + 2x = 0 %3D a. Good guesses: b. # of positive roots: c. # of negative roots: d. # of imaginary roots: e. upper bound f. lower bound g. answers:

Algebra and Trigonometry (MindTap Course List)

4th Edition

ISBN:9781305071742

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter3: Polynomial And Rational Functions

Section3.4: Real Zeros Of Polynomials

Problem 1E: If the polynomial function Px=anxn+an-1xn-1++a1x+a0 has integer coefficients, then the only numbers...

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Question

Number 3 thanks!

Find the zeros of the following polynomials by using the following aids.
Use the rational zero theorem, Descartes's rule of signs, and the theorem on bounds as aids in finding
all real and imaginary roots to each equation.
htt(h-)のでtz(h-)6+c(h-)
X4,-3,-2 are
1. x + 9x? + 26x + 24 = 0
a. Good guesses:
the roots Of epho
b. # of positive roots:
c. # of negative roots:
d. # of imaginary roots:
K+4) x 3+ 9x2+26x+24 (x2+5xt0 "" -ve" -3
X 3
e. upper bound
f. lower bound
+4x2
there Is no bound
5x²+20x+24 (x+4)(x?+5x+e)=ouince lim fA) e
g. answers:
xQしtzXg
6.
6x+24
2. 2x3-7x2 – 16= 0
B The root of the equaionis
a. Good guesses:
Q-01-zメL-×t
There are no negatNe
b. # of positive roots:
c. # of negative roots:
d. # of imaginary roots:
s4009-の1-×hとメhてメナ。メて
D. the
Oこの1-メーローメhtzメ+をメt
bound
3(htメtz×2) (h-X)
the tanation is -
e. upper
f. lower bound
imaginary rootof
hりe
g. answers:
Lhこx
zvて(1E- こX
3. x + 3x³ + 2x = 0
a. Good guesses:
b. # of positive roots:
c. # of negative roots:
d. # of imaginary roots:
e. upper bound
f. lower bound
g. answers:
-ニzX
!4こX

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