3.0 kg block is initially at rest on a frictionless table. A force of 24 N to the west and another force of 18 N towards south are simultaneously applied on the block. What is the direction of the resulting acceleration of the block?

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Chapter5: Newton's Law Of Motion
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A 3.0 kg block is initially at rest on a frictionless table. A force of 24 N to the west and another force of 18 N towards south are simultaneously applied on the block. What is the direction of the resulting acceleration of the block?

A 3.0 kg block is initially at rest on a frictionless table. A force of 24 N to the west and another force of 18 N towards south are
simultaneously applied on the block. What is the direction of the resulting acceleration of the block?
O 37° south of west
0.013° south of west
O 37° west of south
O 0.75 ° south of west
O 0.013° west of south
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Transcribed Image Text:A 3.0 kg block is initially at rest on a frictionless table. A force of 24 N to the west and another force of 18 N towards south are simultaneously applied on the block. What is the direction of the resulting acceleration of the block? O 37° south of west 0.013° south of west O 37° west of south O 0.75 ° south of west O 0.013° west of south Save for Later Submit Answer
Expert Solution
Step 1

Given

Mass m = 3 kg

Applied force

F= 24 N  west

F= 18 N south 

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