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- Compound 1 is an anticoagulant that is extracted from, among other plants, the sweetclover plant, Melilotus Officinalis. However, the compound is moderately toxic and alsofinds use as a rodenticide. Name this compoundIn the following three compounds(1,2,3) arrange their relative reactivity towards the reagent CH3Cl / AlCl3. and justify it.What is going on from compound B to compound C? Can you please select all the options that apply
- The hydrocarbon fluorene was treated with potassium t-butoxide in an acid-base reaction, giving the fluorenide anion and t-butyl alcohol. (a) Which way does the equilibrium lie, and by how much? b) What is the proportion of the fluorenide anion to fluorene? (c) Why is fluorene so highly acidic, considering the pKa of an average alkane is above 50?When the nitrogen-containing aromatic heterocyclic compounds 1 and 2 are treated with HCl, only 1 forms the hydrochloride salt, whereas compound 2 is unreactive. Provide an explanation for this observed reactivity.An unknown hydrocarbon A with the formula C6H12 reacts with 1 molar equivalent ofH2 over a palladium catalyst. Hydrocarbon A also reacts with OsO4 to give diol B. When oxidized with KMnO4 in acidic solution, A gives two fragments. One fragmentis propanoic acid, CH3CH2CO2H, and the other fragment is ketone C. What are thestructures of A, B, and C? Write all reactions and show your reasoning.
- Rank each of the following sets of nitrogen bases in terms of basicity and explain your answerCompound K, L and M are three isomers with the molecular formula C5H10O.Compound K cannot be oxidized, while compound M and L can be oxidized.Oxidation of compound L with hot acidified potassium permanganate,KMnO4 solution yields 2-methylbutanoic acid. When treated with Iodoformreagent, yellow precipitation only occurs in compound K. Fehling test onlyyielded positive results for compound L and negative for compound M andK. Compound M is then reacted with hydrogen chloride, HCl produceschlorocyclopentaneCompound K, L and M are three isomers with the molecular formula C5H10O.Compound K cannot be oxidized, while compound M and L can be oxidized.Oxidation of compound L with hot acidified potassium permanganate,KMnO4 solution yields 2-methylbutanoic acid. When treated with Iodoformreagent, yellow precipitation only occurs in compound K. Fehling test onlyyielded positive results for compound L and negative for compound M andK. Compound M is then reacted with hydrogen chloride, HCl produceschlorocyclopentane (i) Draw the structural formula of compounds K, L and M.
- Compound K, L and M are three isomers with the molecular formula C5H10O.Compound K cannot be oxidized, while compound M and L can be oxidized.Oxidation of compound L with hot acidified potassium permanganate,KMnO4 solution yields 2-methylbutanoic acid. When treated with Iodoformreagent, yellow precipitation only occurs in compound K. Fehling test onlyyielded positive results for compound L and negative for compound M andK. Compound M is then reacted with hydrogen chloride, HCl produceschlorocyclopentane. (ii) Name the type of chemical reaction of compound M when reacted withhydrogen chloride, HCl .Two moles of organic compound ‘A’ on treatment with a strong base gives two compounds ‘B’ and ‘C’. Compound ‘B’ on dehydrogenation with Cu gives ‘A’ while acidification of ‘C’ yields carboxylic acid ‘D’ with molecular formula of CH2O2. Identify the compounds A, B, C and D and write all chemical reactions involved.The crocodile, which can remain under water without breathing for up to 1 h, drowns its air-breathing prey and then dines at its leisure. An adaptation that aids the crocodile in doing so it that it can utilize virtually 100% of the O2in its blood whereas humans, for example, can extract only ~65% of the O2in their blood. Crocodile Hb does not bind BPG. However, crocodile deoxyHb preferentially binds HCO3ꟷ. How does this help crocodile obtain its dinner? Explain your answer.