3.4 amplifier a thermocouple sense way shown in Figure 3.8. What values of R, and R, would give a circuit which has an output of 10 mV for a temperature difference between the thermocouple junctions of 100°C with a copper-constantan thermocouple if the thermo- couple is assumed to have a constant sensitivity of 43 µV/°C? (Note: In 3.4, the differential amplifier should be changed to 'difference amplifier')

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3.4
A differential amplifier is used with a thermocouple sensor in the way shown
in Figure 3.8. What values of R, and R, would give a circuit which has an
output of 10 mV for a temperature difference between the thermocouple
junctions of 100°C with a copper–constantan thermocouple if the thermo-
couple is assumed to have a constant sensitivity of 43 µV/°C?
(Note: In 3.4, the differential amplifier should be changed to 'difference amplifier')
Transcribed Image Text:3.4 A differential amplifier is used with a thermocouple sensor in the way shown in Figure 3.8. What values of R, and R, would give a circuit which has an output of 10 mV for a temperature difference between the thermocouple junctions of 100°C with a copper–constantan thermocouple if the thermo- couple is assumed to have a constant sensitivity of 43 µV/°C? (Note: In 3.4, the differential amplifier should be changed to 'difference amplifier')
Expert Solution
Step 1

The expression for voltage gain of the differential amplifier is,

VoutV2-V1=R2R1where, Vout =output voltage, V2-V1=electro motive force(emf) between the copper-constantan thermocouple junction,R1=input resistanceand R2=feedback resistance.

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