Question

Asked Mar 19, 2019

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3.8 number book 20 - find differentials

cos(pi / 2 + .01)

Step 1

Let's define, y = f (x) = Cos(x)

Hence, dy / dx = - Sin(x)

Hence, dy = - Sin(x).dx

Now, put x = π / 2 and dx = 0.01

Hence, dy = -Sin(π / 2) x 0.01 = -0.01

Step 2

Also, since y = f(x) = Cos(x)

Hence, y + dy = f (x + dx) = Cos(x + dx)

Now, put x = π / 2, dx &n...

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