3.90. There are four numbered balls in a box: 2 white and 2 black. In how many ways can 2 balls be chosen, among which at most one will be black? (a) List all the possibilities. b) Why the number of ways in point a ) cannot be calculated in the following way: we choose one white ball in 1 ways and another ball any of the remaining balls in ways, 1 so together we have 2· 3=6ways?

3.90. There are four numbered balls in a box: 2 white and 2 black. In how many ways can 2 balls be chosen, among which at most one will be black? (a) List all the possibilities. b) Why the number of ways in point a ) cannot be calculated in the following way: we choose one white ball in 1 ways and another ball any of the remaining balls in ways, 1 so together we have 2· 3=6ways?

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter10: Sequences, Series, And Probability

Section10.8: Probability

Problem 32E

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