30KN 30KN 30KN D 30KN 30KN 30kN 30kN G B N. H 30 A h 30° M K -4 mt4 m4mt4m4m-

Q: - hen the galvanized ion sheets com e w ith din ensions (2x1)m.Calulate the um ber of sheets equhed…

A: Given data-→Dimension of galvanised sheet=2×1m→Frictional pressure drop=1 paln→Allowalbe height…

Q: E 450 kN A K N H 40 m 40 m 40 m 40 m 26 m 13 m 3. 26 m 26 m

A: For the given truss only there is one force acting at A,

Q: B 4a E M A L AM = 10a 8a D L

A:

Q: A motor running 1800rpm transmits 10KW of power through a 25mm diameter shaft 1.2m long. What is the…

A:

Q: F = {-20i +25 j + 15k} N 4 m -y A 3 m -4 m

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Q: : Find ES,EF,LS,LF?? Activities Dura Depend 10 10 tion s on A 3 ---- -- 7 18 18 В 5 ----- 7 A D 9 13…

A:

Q: If Fw = 144 N shown in the figure, find FT1 and FT2. FIGURE: 70% 60,

A: Given, Fw = 144 N

Q: 1.97735x10-1m Wáns s 1.6689x10-27 kg ds p O 2r10^6m/s O 3x10^5m/s O 4x10^6m/s 10x10^5m/s O O O

A: given data- mass of the particle = m= 1.6689 x 10-27 kg wave length of the particle = 1.97735 x…

Q: In dead weight tester, the applied load is 0.017 kN, theoretical pressure is 150 kPa. Then the area…

A: Given data:  Magnitude of applied load, F = 0.017 kN. Theoretical pressure, P = 150 kPa. The…

Q: Concrete: fe 30 MPa e - -0.002 Steel: fy- 400 MPa E,- 200,000 MPa A- 1500 mm 3-26M

A: Given data,pressure (fc1)=30 Mpa young modulous (εe1)=0.002fy=400Mpa shear pressure (ES)=200×103Mpa…

Q: F, FM = 12 cm, b = 22 cm, c = 50 cm, Wi = 150 N, Wo = 100 N, 8 = 15° ve ß = 45° FM=? FJ=? W. Wo

A: Given, a= 12cm , b= 22cm and c= 50 cm  W1= 150 N and W0 = 100N

Q: find shear and Binding monont dkagr 5KN/m 3m 5m ThT 3m

A:

Q: 10 Ω R 30 Ω Reg 3 122 12Ω 12Ω 12 Q 60 Ω ww

A:

Q: 20 AN 20 N m -2m F6-8

A: The free body diagram of the beam is as follows: Calculate the moment about point A as follows:…

Q: 3kN m 12 kN/m PA -1.6 m -1.6 m- -1.6 m

A: Drawing the shear force and bending moment diagram.

Q: A 600 D E -Boom `F 375 1800 1650 34.0 kN

A: Consider the boom DEF, Taking moment at…

Q: h- 25 W/m2.C T-5'C 5 T- 100°C 7. 8. 6. L00 Insulated

A:

Q: Ql: Calculate the thermal efficiency of an engine working on the otto eycle. The bore and the stroke…

A: Given        Bore, d = 17 cm      Stroke, l = 30 cm

Q: P P =e{80/RT)(h-hi) R pi || =

A:

Q: B A =Ac =0.1 m? C D T1 T= 66°C

A: Given data, Thermal conductivity of A, B, C and D is,kA=150 W/m·°C,kB=30 W/m·°C,kC=50 W/m·°C,kD=70…

Q: R20 ww For e ned 1-POWER SUPPLY E-20V a-CURRENT ACROSS RESISTANCE R2 VOLTAGE CROSS RESISTANCE RI…

A: Hello. Since your question has multiple sub-parts, we will solve first three sub-parts for you. If…

Q: E, A E, A 2P 3P d,70 mm d 40 mm E210 GPa E10s GPa O- 200 MPa Om-130 MPa a) s0,23 kN b) 59,12 kN )…

A: Given datad1 = 70mmL1 = 3mE1 = 210GPaσmax1 = 200MPad2 =40mmL2 = 1mE2 = 105GPaσmax2 =130MPaThe…

Q: 120mm 16.2KN 16.2KN 10.2kN/m 1m 3m Im thickness of walls 30 mm cross section 60mm 120mm

A: A beam is defined as a structural member subjected to transverse shear load during its…

Q: acity of 75 tons/hr & speed of 50 ft/min. a. 220 mm    b. 370 mm    c. 070 mm    d. 460 mm

A: given:Q=75ton/hrv=50ft/min

Q: 15ON 50N 100N /m EI 8 midspan F2 6 12 El 8 over hang =

A:

Q: 2 KN /m lom. 5m Find The disPlcement E= 200 GPe

A:

Q: which of the following equation is correct equation for change in internal energy du. O a. dU = T ds…

A: The internal energy based on First law of thermodynamics is, dU=dq+dW   For reversible closed system…

Q: Given from a generator: Full-load rating of generator Full-load efficiency of generator : 90% Speed…

A: Since you have posted a question with multiple sub-parts, we will solve the first three subparts for…

Q: O-ring- 2 m 0.2 m `0.25 m

A: Given Data Diameter of the hemisphere is: D=0.25 m The distance from the water surface to the…

Q: 500 N 30 A transmission shaft, supporting two pulleys A and B and mounted between two bearings C,…

A:

Q: 5V high-capacity V-belt carries a load horsepower of 12.5V, but a service f 1.5 must be used. Pulley…

A:

Q: 3m 75N 60C b- 110 N.m. d- 114.5Nm. c- 115 N.m. a- 112.5 N.m. K

A:

Q: ne equivalent resistance be

A: ANSWER R23+ R1= 97.867Ω

Q: 4 kN E В F 3 m A L K J IH 12 m, 6 @ 2 m A B 15.781kN 14.908KN 13.334kN

A:

Q: members DE, DJ, EJ, and IJ. 2 KN XNK 8m 8m 8m 8m L K J H 1 kN 8m 3 KN 1.5m 2m 8m

A: To find force in member DE,DJ,EJIJ

Q: #1--- #2 #3 A V #1 #2 #3 <<<<<< #E #6 T(°C) 300 200 TE 100 ~~~ B α 0 L+a 20 C Pb-Sn System 40 D #4…

A: Given: The Sn Pb diagram consists of different phases. The number 1 indication shows the complete…

Q: QUES cause failure of the link by buckling. P. 30 r= 1.4 m 1.92 m D 0.56 m

A:

Q: A gas engine valve spring is loaded to 35kgf when the valve is closed & 52kgf hen the valve is open.…

A:

Q: Lecture 6: Balanced Delta Load IBR VeN VRY BR 21.8 IRY 82,V -21.8 IYB VYB.

A: The voltages in the three-stage power framework are delivered by a simultaneous generator . In a…

Q: 30N/m 0.4kg -Fa WwW

A: For solution refer below images.

Q: A= -i +3j+2k and B=21-4j+2k. 1-A+B 2-A-B 3-A.B 4-AxB

A:

Q: اذا كان المتجه A= -i +3j+2k and B=21-4j+2k. 1-A+B 2-A-B 3-A.B 4-AxB

A:

Q: pe th (L-2.5 m, kl-300 kN/m, k2-100 kN/m, m-15 ton, Exirig"30 GPa, Ikirig 3000 cm)

A: For solution refer below images.

Q: 8kN 15 kN/m 20 kN-m m1 m- 2 m- B -3 m

A:

Q: 20KN 30KN 40KN D F II 10KN 50KN 4u per spai 1. Reactions 2. Bar Forces a. By Method of Joints AC АВ…

A:

Q: F126KN 180KN 26 -3m 1.5m 48 65° 145KN V165 KN

A: Drawing the system of force as shown below – Let us take point A as an origin of the coordinate…

Q: etermine Ra. Rb and Rc. R=0.8m R=1.0m 367 N 367 N 426 N 426 N 426 N B

A: GIVEN:- Radius of sphere 1,3,5: R=1m Radius of sphere 2,4: r=0.8m weight of sphere 1,3,5: W=426N…

Q: ri= 2t-1 h=3ピ-t 2= 3++1 h2 = 4t-1

A: For solution refer below images.

Q: 41868 KJ/K nd (70%) of ming the co

A: Given: C.V = 41868 KJ/Kg V1'=  V2+ 0.7( V1- V2)V2'= V2+ 0.3(V1- V2) P1'= 1.3 bar          P2'= 2.6…

Q: 8. Given=1m, B=4X105T Area, A=TTY°= 3·14x(1)= 3-14 m' emf, E=31•4MV=3|·4 x1Ō E= 3•14 X102V. 2 w=?

A: By applying EMF expression we have calculated omega. Which is 250rps.