30z2 – 23z + 5 Evaluate J (2z – 1)²(3z – 1) dz, C : |2| = 1 (counterclockwise). |

Algebra for College Students
10th Edition
ISBN:9781285195780
Author:Jerome E. Kaufmann, Karen L. Schwitters
Publisher:Jerome E. Kaufmann, Karen L. Schwitters
Chapter13: Conic Sections
Section13.1: Circles
Problem 48PS
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30z2 – 23z + 5
Evaluate
J (2z – 1)²(3z – 1)
dz, C : |2| = 1 (counterclockwise).
Transcribed Image Text:30z2 – 23z + 5 Evaluate J (2z – 1)²(3z – 1) dz, C : |2| = 1 (counterclockwise).
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