b) y = -x -1 -u) 4 = 3x +5 -ài) a) 2x +3 %3D y = 4x -) -ài, Bub ci) from il cis from ei) Sub = 4n - | = 3x +5 = 2ut3 = -X -7 O = 2n-4 6 = yx + 12 2x = 4 4n =- 12 n=2 n= -3 Put in Put n= -3 in eg u) i) y = -(-3) - 7 = 2 x 2+ 3 y = -4 %3D Point of intersection (2,7) point d inkisechon (-3,-4) (c) y= }* Ix -2 i) x + 3 Bub Brom uj eg i) = Lx - 2 2. 3 x +3 Put n= 20 In eg ü) 4= 20-2 うy= -12 れ:-20 Point of inkeraechion of 1 question are allowed (-20,-12) 3 subparts

College Algebra (MindTap Course List)
12th Edition
ISBN:9781305652231
Author:R. David Gustafson, Jeff Hughes
Publisher:R. David Gustafson, Jeff Hughes
Chapter6: Linear Systems
Section6.2: Guassian Elimination And Matrix Methods
Problem 84E: Explain the differences between Gaussian elimination and Gauss-Jordan elimination.
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Question
6) y= -x -7 -i)
4 = 3x +5 -ài)
a)
2x + 3
%3D
y = 4x -) -ài,
%D
Bub
ci) from il
cis from ei)
Sub
= 4n - 1
= 3x +5
= -X -7
O = 2n-4
6 = 4x +12
2n = 4
4n =- 12
n= 2
K= -3
Put
in
i)
Put n=-3 in eg u)
Y = -(-3) - 7
Y = -4
= 2 x2+ 3
%3D
Point of inter section
(2,7)
point d inkisechon (-3,-4)
(c) y=
Ix -2 i)
%3D
n + 3
Bub
Brom uj
eg i)
= Lx - 2
3 u + 3
Put n= 20
In
(n ta
y = {(-20) - 2 y= -12
2= - 20
Point of inkraechion
3 subparts of Į question are allowed
(-20,-12)
Transcribed Image Text:6) y= -x -7 -i) 4 = 3x +5 -ài) a) 2x + 3 %3D y = 4x -) -ài, %D Bub ci) from il cis from ei) Sub = 4n - 1 = 3x +5 = -X -7 O = 2n-4 6 = 4x +12 2n = 4 4n =- 12 n= 2 K= -3 Put in i) Put n=-3 in eg u) Y = -(-3) - 7 Y = -4 = 2 x2+ 3 %3D Point of inter section (2,7) point d inkisechon (-3,-4) (c) y= Ix -2 i) %3D n + 3 Bub Brom uj eg i) = Lx - 2 3 u + 3 Put n= 20 In (n ta y = {(-20) - 2 y= -12 2= - 20 Point of inkraechion 3 subparts of Į question are allowed (-20,-12)
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