31 (ß 2.33) = P 31) S.2139 -37(1 =p(zz.41) = l-piz < 4) 3409 1-. 659) %3D 그34.1/. 시

Holt Mcdougal Larson Pre-algebra: Student Edition 2012
1st Edition
ISBN:9780547587776
Author:HOLT MCDOUGAL
Publisher:HOLT MCDOUGAL
Chapter11: Data Analysis And Probability
Section: Chapter Questions
Problem 8CR
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For questions 1 and 2, you need to draw and shade the distribution curves...

1. Suppose that 31% of adults have at least one tattoo. If you sample 90 random
adults, what is the probability that 33% or more of them have a tattoo?
33 - ,31
plê 2.33) = P
|
37(1 -.31)
4.
2139
=p(zz.41)
|-plz< .4):
· 3409
Y 34.11.
1-. 659)
orny
2. Instead, if you sample 300 random adults, what is the probability that
33% or more of them have a tattoo?
.33--3)
B00 (.02)
P(p 2.33 | = P
PSI-P)
31- (1
J.a139
300
= p(z 2.75 ) = 1-p(lzc.75)
|- .7734 -2266
Z <.75
11
* 22.67.
Transcribed Image Text:1. Suppose that 31% of adults have at least one tattoo. If you sample 90 random adults, what is the probability that 33% or more of them have a tattoo? 33 - ,31 plê 2.33) = P | 37(1 -.31) 4. 2139 =p(zz.41) |-plz< .4): · 3409 Y 34.11. 1-. 659) orny 2. Instead, if you sample 300 random adults, what is the probability that 33% or more of them have a tattoo? .33--3) B00 (.02) P(p 2.33 | = P PSI-P) 31- (1 J.a139 300 = p(z 2.75 ) = 1-p(lzc.75) |- .7734 -2266 Z <.75 11 * 22.67.
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