menu
bartleby
search
close search
Hit Return to see all results

*32. A 10-kg block rests on a table for which the coefficientof static friction between the block and the tabletop is exactly0.4. The block is connected to a knot by a horizontal string.Another block hangs from the knot, and another string goesup at an angle 30° to a wall, as shown at right. How large canthe mass m be before the 10-kg block begins to move to theright?30°10 kgm

Question
*32. A 10-kg block rests on a table for which the coefficient
of static friction between the block and the tabletop is exactly
0.4. The block is connected to a knot by a horizontal string.
Another block hangs from the knot, and another string goes
up at an angle 30° to a wall, as shown at right. How large can
the mass m be before the 10-kg block begins to move to the
right?
30°
10 kg
m
help_outline

Image Transcriptionclose

*32. A 10-kg block rests on a table for which the coefficient of static friction between the block and the tabletop is exactly 0.4. The block is connected to a knot by a horizontal string. Another block hangs from the knot, and another string goes up at an angle 30° to a wall, as shown at right. How large can the mass m be before the 10-kg block begins to move to the right? 30° 10 kg m

fullscreen
check_circleAnswer
Step 1

Consider the mass of the block of 10kg be m1, the coefficient of the static friction be µs, the tension in the horizontal string be T, the normal reaction on the block of 10kg be N, the tension in the string at given angle be T1,

 

Consider the free body diagram of the block of 10kg.

うT
10 kg
F=LN
W1
help_outline

Image Transcriptionclose

うT 10 kg F=LN W1

fullscreen
Step 2

Apply static equilibrium condition along the vertical direction on the block.

ΣΗ-0
N-w0
N-mg 0
N-(10 kg) (9.81 m/s?)=0
N 98.1 N
help_outline

Image Transcriptionclose

ΣΗ-0 N-w0 N-mg 0 N-(10 kg) (9.81 m/s?)=0 N 98.1 N

fullscreen
Step 3

Apply static equilibrium condition along th...

ΣΕ-0
T F 0
T-μ.Ν 0
T-(0.4)(98.1 N) 0
T=39.24Ν
help_outline

Image Transcriptionclose

ΣΕ-0 T F 0 T-μ.Ν 0 T-(0.4)(98.1 N) 0 T=39.24Ν

fullscreen

Want to see the full answer?

See Solution

Check out a sample Q&A here.

Want to see this answer and more?

Our solutions are written by experts, many with advanced degrees, and available 24/7

See Solution
Tagged in

Science

Physics

Friction

Related Physics Q&A

Find answers to questions asked by student like you

Show more Q&A add
question_answer

Q: the question is the image

A: The equation for the current passing through the wire is

question_answer

Q: An object in uniform circular motion is accelerating as you observed in this project. How can this b...

A: A circular motion is the motion of an object undergoing circular path about a common point. the circ...

question_answer

Q: Townsend 1.21: A certain photodetector can resolve the time of arrival of a photon to within 2. 108 ...

A: In an anticoincidence experiment, only one of the detectors should receive a signal within a period ...

question_answer

Q: Car A uses tires for which the coefficient of static friction is 0.329 on a particular unbanked curv...

A: When an object is moving in a circular path, there is a force acting on it towards the center of the...

question_answer

Q: In a particular Cartesian coordinate system, the y and z-components of the acceleration are zero and...

A: Hey, since there are multiple subparts posted, we will answer first three questions. If you want any...

question_answer

Q: Can you help me on question two?

A: Let m be the slope and b be the y-intercept in the equation of a straight line.Here y depends on x, ...

question_answer

Q: Water falls without splashing at a rate of 0.270 L/s from a height of 3.20 m into a 0.650-kg bucket ...

A: Given information:Volume flow rate of water (V) = 0.270 L/sMass of the bucket (M) = 0.650 kgHeight f...

question_answer

Q: A bicycle wheel is mounted on a fixed, frictionless axle. A massless string is wound around the whee...

A: Given information:Force applied in the wheel = FMoment of inertia of the wheel = I = kmr2Where “m” i...

question_answer

Q: What is the velocity of an object of mass 1 kg which has 200 J of k.e?

A: Click to see the answer

Sorry about that. What wasn’t helpful?