32. A 59.46-g sample of Ba(OH)2 is dissolved in enough water to make 1.20 L of solution. How many milliliters of this solution must be diluted with water in order to make 1.00 L of 0.100 M Ba(ОН):? a. 346 mL b. 289 mL c. 595 mL d. 347 mL e. 71.4 mL

Q: In the laboratory you dilute 4.23 mL of a concentrated 12.0 M hydroiodic acid solution to a total…

A: Given  Initial Volume ( V1 )             = 4.23 mL  Initial Concentration ( M1 ) = 12 M  Final…

Q: For the reaction: NazCO3(aq) + NICI2(aq) → NICO3(s) + 2NACI(aq) How many milliliters of 0.47 M NICI2…

A: We will use stoichiometric calculations to calculate volume of NiCl2, then find number of moles of…

Q: How many g of MgCl2  are dissolved in the solution?

A: Given :- volume of solution = 0.300 L  molarity of MgCl2 solution = 1.85 mol/L  To calculate :- Mass…

Q: Boric acid, H3BO3, is commonly used in eyewash solutions in chemistry laboratories to neutralize…

A:

Q: How many moles of solute are in solution a) 765 g of NaCl solution which has a concentration of…

A:

Q: In the laboratory you dilute 4.46 mL of a concentrated 6.00 M hydrochloric acid solution to a total…

A:

Q: 1. A blood serum sample is analyzed and found to contain 102.5 µg Ca²*/mL serum. The density of the…

A: 3) Given that: Molarity of Cr3+ = 0.125 M Molarity of MnO4- = 0.200 M Volume of MnO4- = 12.00 mL

Q: Apollo 13 Lunar Mission You are a NASA engineer. You are the chief engineer for the Apollo 13…

A: Given data; 6.7×1025 particles of NaOH are present There are three astronauts and each will emit 500…

Q: he standardization of iodine solution was conducted using 10.0 mL of a standard 1.00 m ith the…

A: Given, Volume of acid  = 10.00 mL Density = 1.00 mg/mL Mass = V × d   = 10.00 × 1 = 10.0 mg MMoles…

Q: To what volume should you dilute 46 mL of a 12 M stock HNO3 solution to obtain a 0.122 HNO3…

A: Molarity is the concentration of a solution in moles of solute per liters of solution.

Q: How many grams of Mg3(PO4)2 are needed to make 3.000 L of a 2.500 M solution ? The GFW for magnesium…

A: The GFW of Mg3(PO4)2 = 262.87g

Q: f 20. g of AgNO3 is available, what volume of 0.40 M AgNO3   solution can be prepared? Volume =…

A: Molarity is the moles of solute per liter volume of solution. It is represented as M.

Q: 5 A,B,C,D

A:

Q: Suppose you need 300 mL of 0.250 M NaCI, but the only supply of sodium chloride you have is a…

A: Given: The molarity of the NaCl solution after dilution = 0.250 M The volume of the NaCl solution…

Q: A chemist has a 235.0 mL solution of sodium bisphosphate with a concentration of 3.75 M. The diluted…

A: Concentrated solution – Volume, V1 = 235 mL Molarity, M1 = 3.75 M Diluted solution – Molarity, M2 =…

Q: A solution of NaOH is 95% by mass and has a density of 1.2 g/ml. How many mL of water should be…

A: Given data is as follows: The mass of NaOH = 95 g in 100 g of solution ( 95% by mass ) Density of…

Q: 2 NaBH4(aq) + H2SO4(aq) → 2 H2(g) + Na2SO4(aq) + B2H6(g) What volume, in mL, of a 0.528 M solution…

A: Molarity of a solution is given by dividing the number of moles of solute with volume of solution…

Q: 6. 100.0 mL of a silver nitrate solution is added to 98.75 g of a water sample. The density of this…

A: Number of Mole- Ratio of given mass of substance to the molar mass of substance is called number of…

Q: (a) How many milliliters of a stock solution of 13.0 M HNO3 would you have to use to prepare 0.500 L…

A:

Q: A 51.0 mL51.0 mL aliquot of a 1.40 M1.40 M solution is diluted to a total volume of 248 mL.248 mL. A…

A: Given: Initial volume = V1 = 51.0 mL Initial Molarity = M1 = 1.40 M Total volume = V2 = 248 mL

Q: what the concentration of NaCl in the original solution?

A: Given :- mass of NaCl = 0.505 g              Initial volume of solution = 75.0 mL   To calculate :-…

Q: A student removes 25 mL of 3.0 M NaOH and dilutes it to final volume of 350 mL. What is the…

A: Given,  Initial volume, V1 = 25 ml  Initial concentration, S1 = 3.0 M  Final Volume, V2 = 350 ml…

Q: A 22.7-g sample of HF is dissolved in enough water to give 2.0 × 102 mL of solution.  What is the…

A: Given: weight of HF=22.7gvolume of solution = 2.0×102mlconcentration of a solution is defined as…

Q: 1. Prepare 100 ml of 0.2 N NAOH? (atomic mass: Na=23, O=16, H=1) 2. What is the normality of a 500ml…

A:

Q: A solution of 0.5 M NaOH of volume 100 ml was diluted to 400 ml. What was the Molarity of the…

A: Given: Molarity of initial NaOH solution is 0.5 M. Volume of initial NaOH solution is 100mL. Volume…

Q: 1. Muriatic solution is prepared by dissolving 44.6 g of acetone (OC(CH.),) in water to produce 1.50…

A:

Q: Boric acid, H3BO3, is commonly used in eyewash solutions in chemistry laboratories to neutralize…

A:

Q: Consider the balanced equation of  KIKI reacting with Pb(NO3)2Pb(NO3)2 to form a precipitate.…

A: • Concentration = No. of molesVolume (L)• Mass = No. of moles x molar mass• Molar mass of PbI2 = 461…

Q: 4.30 A sample of concentrated nitric acid has a density of 1.41 g/mL and contains 70.0% HNO3 by…

A: Given:Density = 1.41g/mLMass % of HNO3 = 70.0%We need to find the mass of HNO3 and Molarity of…

Q: Glucose (molar mass=180.16 g/mol) is a simple, soluble sugar. Glucose solutions are used to treat…

A: Molarity is given by the ratio of number of moles per litre of the solution. Molarity =(Number of…

Q: D 2.3 x 10 mol/dm 3 25.0 cm of 0.100 mol/dm³ aqueous sodium hydroxide is neutralised by 24.6 cm° of…

A: 1 dm3 = 1000 cm3.   25.0 cm3 0.100 mol/dm3 NaOH solution contains (25/1000)×0.100 = 0.0025 mol NaOH.…

Q: How many grams of aluminum hydroxide will be formed from 55.0 mL of a 1.50 M potassium hydroxide…

A: Answer: This question is based on stoichiometric calculation where moles of KOH will be converted…

Q: (b) An unknown mass of Na;PO<(s) is dissolved in water to form 50.00 mL of solution. This is…

A:

Q: 43. A 10.00 mL sample of 2.05 M KNO3 is diluted to a vol- ume of 250.0 mL. What is the concentration…

A: As per our honor code we are authorized to solve only one question in one request. We’ll answer the…

Q: 35. To what volume should 675 g of AgNOs be diluted in order to prepare a 0.25 M solution? 36. What…

A: The amount of solute in a given volume of solution is measured in molarity (M). The moles of a…

Q: A Chemistry teacher needs to make 0.45 L of 0.2 M NaOH solution for a class experiment. What volume…

A:

Q: Suppose that 2.89 L of 6.75 M potassium carbonate is added to 1.38 L of 1.57 M magnesium nitrate.…

A: In this question, potassium carbonate is added to magnesium nitrate, after reaction , total…

Q: Suppose 0.353 g of ammonia reacts with 18.8 mL of a hypobromite solution. Calculate the…

A:

Q: A 501-mL sample of a 0.184-M CaCl2  solution is left on a hot plate overnight; the following…

A: Given: Initial volume of sample=501 mLInitial molarity of sample=0.184 MFinal molarity of…

Q: Q. A 12.5% (w/w) NICI2 (129.6l g/mol) solution has a density of 1.149 g/mL. Calgulate(a) the molar…

A:

Q: 24.71 cm (24.71 m) of this solution is delivered from a buret, what amount of HCI has been…

A: Molarity is defined as the ratio of the number of moles of solute to the volume of solution in…

Q: A 25.0 mL sample of a 30.0% HF solution has a density of 1.101 g/mL. The sample is diluted to a…

A: Given information,    Initial volume of the solution is 25.0 mL.    Final volume of the solution is…

Q: A 0.650 ?0.650 m aqueous solution of KBrKBr has a total mass of 86.0 g.86.0 g. What masses of solute…

A: we have to calculate the mass of KBr and H2O

Q: An unknown mass of Na3PO4(s) is dissolved in water to form 50.00 mL of solution. This is Solution A.…

A:

Q: What volume of 0.36 mol/L sodium hydroxide solution can be prepared from 85.0 ml of a 6.5 mol/L…

A:

Q: Glucose (molar mass=180.16 g/mol) is a simple, soluble sugar. Glucose solutions are used to treat…

A: Molar mass of glucose = 180.16g/mol Mass of glucose = 233.8g  Volume of water = 500mL

Q: If 330g of HCL solution is 23 HCL w/w%. What is the mass of HCl?       a.     50 ml     b.…

A: Mass of HCl solution = 330 g  Mass percent  of HCl = 23  Mass of HCl = ?

Q: A solution of HCI gas dissolved in water has 28.22 g of HCI per 100.0g of solution, and its density…

A: Using formula of Molarity we can solve this problem.

Q: A student makes a solution by dissolving 10.095g of Ca(NO3)2 (MM=164.09 g/mol) in 300 mL of water…

A: Given 10.095g of Ca(NO3)2 (MM=164.09 g/mol) in 300 mL of water  Molarity is to be determine Diluted…

Q: In the laboratory you dilute 5.20 mL of a concentrated 6.00 M hydroiodic acid solution to a total…

A: The Concentration of the dilute solution can be calculated as,  M1V1 = M2V2 where, M1 = Initial…