**38. A 4-kg toy jet sled is accelerated forward from rest by escaping CO2 from the jet engineAfter the sled has gone 10 m, the engine shuts off, leaving the sled going 10 m/s. The coefficientof friction between the sled and the snow is 0.2. How much force did the jet produce? How farwill the sled slide after the jet shuts off?

Question
Asked Oct 13, 2019
**38. A 4-kg toy jet sled is accelerated forward from rest by escaping CO2 from the jet engine
After the sled has gone 10 m, the engine shuts off, leaving the sled going 10 m/s. The coefficient
of friction between the sled and the snow is 0.2. How much force did the jet produce? How far
will the sled slide after the jet shuts off?
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**38. A 4-kg toy jet sled is accelerated forward from rest by escaping CO2 from the jet engine After the sled has gone 10 m, the engine shuts off, leaving the sled going 10 m/s. The coefficient of friction between the sled and the snow is 0.2. How much force did the jet produce? How far will the sled slide after the jet shuts off?

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check_circleExpert Solution
Step 1

The frictional force exerted on the toy jet and the snow is,

Substitute the values,

F,(02)(4kg)(9.80m/s')
=7.84N
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F,(02)(4kg)(9.80m/s') =7.84N

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Step 2

The work done by the jet engine is equal to the kinetic energy of the jet is calculated as,

Substitute the values,

-mу
2
W(4kg)(10m/s)
и
2
200J
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-mу 2 W(4kg)(10m/s) и 2 200J

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Step 3

The work done by the distance of the jet moved in...

w Fd
W
d
200J
d
7.84N
25.5m
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w Fd W d 200J d 7.84N 25.5m

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