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Introductory Circuit Analysis (13th Edition)
Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
Chapter1: Introduction
Section: Chapter Questions
Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...
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Instructions: In Order to answer the given the first picture is the guide to answer the given please provide detailed step by step solution.

Note: Substitution and Elimination are Required : To answer the given you need to follow the solution guide
ulth 3H 3F
Transcribed Image Text:ulth 3H 3F
The impedances are now: V(s) Z(s) = I(s) Laplace Transtorm Resistor: Z(s) =R Inductor: Z(s) = sL Capacitor: Z(s) Step 1 Convert to imped ance. step a Mosh Anolysis ΙΩ 5Ω ww u(1) 1H (1) 3. %3D Ia ©57,+sI, +-T,)=0 +3 (s+S+흥) Lu-흥 20 3 Elimination Step 3 Step -3 [(st377,-37,=1] (s+3 )I, - 37,= / 912=-3 9I, = 0 (55+s*+3JI3 - 31, = 0 - 3I, + (s²4 55+3)I, = Jutition IIa =-3 (53+8524/85+9II1=0 (-s³-85*-185)Fa = -3 (S+ 3)I, - 3(- - 3 Ia ==53-85^_11s - 3 (S+3)I, = 1+ 3. 53+852+185 StS S+3 ell
Transcribed Image Text:The impedances are now: V(s) Z(s) = I(s) Laplace Transtorm Resistor: Z(s) =R Inductor: Z(s) = sL Capacitor: Z(s) Step 1 Convert to imped ance. step a Mosh Anolysis ΙΩ 5Ω ww u(1) 1H (1) 3. %3D Ia ©57,+sI, +-T,)=0 +3 (s+S+흥) Lu-흥 20 3 Elimination Step 3 Step -3 [(st377,-37,=1] (s+3 )I, - 37,= / 912=-3 9I, = 0 (55+s*+3JI3 - 31, = 0 - 3I, + (s²4 55+3)I, = Jutition IIa =-3 (53+8524/85+9II1=0 (-s³-85*-185)Fa = -3 (S+ 3)I, - 3(- - 3 Ia ==53-85^_11s - 3 (S+3)I, = 1+ 3. 53+852+185 StS S+3 ell
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