Question 6 conservation of momentum 8.12 x vi+ (-8x3) + 1212 xvi = -1278×6+8×3V=573x60 +0= (10+60) vV-3x603m/s60 kgBefore7010 [V=2.57m/s)Om/s10 kg1.5m/sAfter? m/s10 kg

Name: Question 6 conservation of momentum 8.12 x vi+ (-8x3) + 1212 xvi = -12
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Description: Question 6 conservation of momentum 8.12 x vi+ (-8x3) + 1212 xvi = -1278×6+8×3V=573x60 +0= (10+60) vV-3x603m/s60 kgBefore7010 [V=2.57m/s)Om/s10 kg1.5m/sAfter? m/s10 kg

Given data: Mass of runner (m1) = 60 kg Initial velocity of runner (u1) = 3 m/s Mass of box (m2) =…

Answered: 3m/s 60 kg Om/s 10 kg ? m/s 10 kg

Science

Physics

3m/s 60 kg Om/s 10 kg ? m/s 10 kg

An Introduction to Physical Science

14th Edition

ISBN:9781305079137

Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres

Publisher:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres

Chapter1: Measurement

Section: Chapter Questions

Problem 7FIB

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