3s2 + 5s + 1 (s)= (s2 + 15s + 34) %3D

Q: (D³ – 3D + 2)y = -7 5.

A: Solve the following

Q: 8. -y-Z=-2 -y-D4

A: Substitute y=-4 into the first equation.

Q: Determine. '{F}. 4s2 + 3 sF(s) – SF(s) – 2F(s) = - s + 4s

A: Rewrite the given equation.

Q: b) Find L- 2s2-4s+20 s+2

A:

Q: 3) Chain rule: y = (3x2 - 3x- 2)2 1/2

A:

Q: 4) y=-4 6-5-4-3-2 -1 $6 x

A: We have to draw the graph of y=-4

Q: Determine L-1{F} if -3s2 + 20s – 25 F(s) (8 – 3)(s² – 2s + 5)'

A:

Q: -4s se (b) L-1{ - } s2 -8s+20

A: Heaviest function is defined by,                               Ht-a=0t<a1t≥a

Q: 8s2 -4s+12 1. F(s) s3 +4s

A:

Q: 3) -x² – 4x + y + 3 = 0 -x? - 3x + y + 3 = 0

A: Given that: -x2-4x+y+3=0             ..........(1)-x2-3x+y+3=0     .........(2)               NOTE:…

Q: g (x) =2 6+ -8 -6 -4 -2 2 4 2.

A: let y=x13 g(x)=2x13 (Stretches y=x13 2 units along Y direction)

Q: Simplify

A: Given: -2r4s-3-2

Q: X- 2 ligy 反-2

A: Given: Let L=limx→4x-2x-2 To Find: To evaluate the given limit.

Q: Determine: 2s2+10s . С-1 l(s²-2s+5)(s+1))

A:

Q: 3s +25 5) y=L-1 s² +6s+13

A: In the case of multiple questions we are ordered to solve first unless asked specific one. So I am…

Q: S2 -4S2 +28z =〇 + 2 8z -0 Sy 8x2

A: This is a problem of the partial differential equations.

Q: Find L-1 () 5-2s s²+7s+10

A: Given, L-15-2ss2+7s+10

Q: 1+z-2 = 0

A: Let the given equation be ex-1+x-2=0 and express the equation in lambert form W(xex)=x.   Lambert…

Q: -1 -2s [s²

A:

Q: 3s +25 5) y=L-1 |s²+6s+13 ]

A: Since you have asked multiple question, we will solve the first question for you. If you want any…

Q: L-1 (s³+3s²-s-3) . (s²+2s+5)²,

A:

Q: Determine L-1 1 s²-3s-4 (s-3)(s-1)².

A:

Q: D² - 4D + 4)y= e²x sec²x (by Reduction of Order)

A: Solution :

Q: 9s + 7 F(s) = 2s2 + 2s + 4

A: Given: F(s)=9s+72s2+2s+4

Q: 3s +25 5) y=L-1 |s²+6s+13

A:

Q: 4 (a² - y²)² 4. g(x) = (3x² + 4x - 5)5 3. 2 =

A:

Q: V10 r (Vx² + I – Væ² – 1) - - V5 Vx4 – 1

A:

Q: e-7x - 2e3 et f (x) = e- *+16e10* + 2e-4z

A: (a) Consider the provided limit, limx→-∞e-7x-2e3x-exe-x+16e10x+2e-4x Evaluate the provided limit.…

Q: 1) -3s2-12s-8] L-1 의 (s+2)³

A:

Q: 4. P(x)-12x+13x2-1; r-1

A: Topic =Polynomial

Q: 21. y = 2 + 3 sec(2x – 7)

A: sec(2x-π)=sec(π-2x)=-sec(2x)

Q: Lime 4-X X-24 ら-Jx2キラ

A:

Q: x³dx 3. S х2+3х+2

A: We will solve the problem

Q: | (cscx + 3 e3* š + 6" – 7) d.æ -

A: Given: ∫(csc2x+3e3x+6x-7)dx

Q: Find ()() 24e-5s + 2-9 L-1 s2 + 8s + 17

A:

Q: half of 2+2?

A:

Q: y >- 3/5x -1

A: we will solve this inequality by the below-mentioned method and also a graph of the given equation…

Q: Find L-1 [ 2s-3 s2-3s+2.

A:

Q: y = -x-4 X-y= -6 (-5,1)

A:

Q: 2(3r2 + 4r +2) – 3(-r2 +4r – 5)

A: We have to simplify the expression: 23r2+4r+2-3-r2+4r-5 Simplifying by removing parenthesis, we get…

Q: 3. 2S-1 s2-6s+18

A:

Q: (z + 2)(3z + 1)

A:

Q: (z-2)

A: Expression  x*x3

Q: y3Dmx+b 6. 0 510 1S y2 3 4

A:

Q: Show the solution

A: Given differential equation is

Q: |sgn(-2.4)| + sgn(-0.2)

A:

Q: 6. %3D 시(0e)- 시(2K)= / = 6

A: Given,          ∂''u∂t2=6∂''u∂x2,    ϕ<x<2⇒∂2u∂t2=6∂2u∂x2 ,     0<x<2,          (1) and…

Q: 25. y = V2r + 3 %3D

A: Since you have asked multiple question, we will solve the first question for you. If youwant any…

Q: 3s+6 F(s) = s2-4s-5

A:

Q: S (2x-4x-D²

A: