·S.3x53x4+6x3-3x2-6x+ In-dx using method of partial fractions./]+C=-=-]+C2] + c2) 16² ] + CEvaluateO x²-4x(x-1) 1/6(x+2) 16/3-2x+1O x²-2r+ In√(x-1) 1/6(x+2) 16(x+1) 1/22x²–2x −10[(x − 1- 1(x-1) 1/6(x+2) 16/3(x+1) 1/2O x² - 4x+ In(x-1) 1/6(x+2) 16/3(x+1)¹/22

This question related to integration using partial fraction.

3x5 Evaluate 3x4+6x³-3x2-6x O x²-4x (x-1) 1/6(x+2) 16/3 +In 2 X+1 Ox²-2r (x-1) 1/6(x+2) 16/3- +In 2 (x+1) 1/2 x²=2x-10[- (x-1) 1/6(x+2) 16/3- (x+1) 1/2 +C + In *(x-1) 216²] + C (x-1) 1/6(x+2) 16/3 (x+1) 1/2 •·S= O x²-4x 2 -dx using method of partial fractions. ²]+C +C

3x5 Evaluate 3x4+6x³-3x2-6x O x²-4x (x-1) 1/6(x+2) 16/3 +In 2 X+1 Ox²-2r (x-1) 1/6(x+2) 16/3- +In 2 (x+1) 1/2 x²=2x-10[- (x-1) 1/6(x+2) 16/3- (x+1) 1/2 +C + In *(x-1) 216²] + C (x-1) 1/6(x+2) 16/3 (x+1) 1/2 •·S= O x²-4x 2 -dx using method of partial fractions. ²]+C +C

College Algebra (MindTap Course List)

12th Edition

ISBN:9781305652231

Author:R. David Gustafson, Jeff Hughes

Publisher:R. David Gustafson, Jeff Hughes

Chapter6: Linear Systems

Section6.CR: Chapter Review

Problem 59E: Decompose into partial fractions. 4x3+3x+x2+2x4+x2

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Question

·S.
3x5
3x4+6x3-3x2-6x
+ In
-dx using method of partial fractions.
/]+C
=-=-]+C
2] + c
2) 16² ] + C
Evaluate
O x²-4x
(x-1) 1/6(x+2) 16/3-
2
x+1
O x²-2r
+ In
√(x-1) 1/6(x+2) 16
(x+1) 1/2
2
x²–2x −10[(x − 1
- 1
(x-1) 1/6(x+2) 16/3
(x+1) 1/2
O x² - 4x
+ In
(x-1) 1/6(x+2) 16/3
(x+1)¹/2
2

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