Algebra & Trigonometry with Analytic Geometry
13th Edition
ISBN:9781133382119
Author:Swokowski
Publisher:Swokowski
Chapter10: Sequences, Series, And Probability
Section: Chapter Questions
Problem 49RE
Related questions
Question
![3z
dz
(1 – 4z–2z²)²
1
|V3+ vZ (z+ 1)|
1
|V3+ vZ (z + 1)|
In
3
z+1
z+1
4 (3 – 2 (2 + 1*)] " 3–4(z+1 2 +c
4 [3 – 2 (z + 1*)] 6-4 (z+1)² zy6
3– 2(2 + 1)* |
3- 2(2 +1)
Option 1
Option 2
|V3+ vZ (z + 1)|
=In
|3 – 2(z + 1)² |
š+ v2 (z + 1)|
+C
3
z+1
z+1
1
3 (3 – 2 (2 + 1°)]¯ 6-4(+1) 2 +c
3 [3 – 2 (x + 1*)] 3-4(z+ 1)²¯zV6
3-2(z + 1)|
Option 3
Option 4
option 5: none of these](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe6f75759-73ff-4df4-aeb3-91ff18b1338e%2Fdb7ecc63-8e41-4b21-8ead-a38c48cf9c2f%2F6x7ixprh_processed.png&w=3840&q=75)
Transcribed Image Text:3z
dz
(1 – 4z–2z²)²
1
|V3+ vZ (z+ 1)|
1
|V3+ vZ (z + 1)|
In
3
z+1
z+1
4 (3 – 2 (2 + 1*)] " 3–4(z+1 2 +c
4 [3 – 2 (z + 1*)] 6-4 (z+1)² zy6
3– 2(2 + 1)* |
3- 2(2 +1)
Option 1
Option 2
|V3+ vZ (z + 1)|
=In
|3 – 2(z + 1)² |
š+ v2 (z + 1)|
+C
3
z+1
z+1
1
3 (3 – 2 (2 + 1°)]¯ 6-4(+1) 2 +c
3 [3 – 2 (x + 1*)] 3-4(z+ 1)²¯zV6
3-2(z + 1)|
Option 3
Option 4
option 5: none of these
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