4 Find (if possible) a. AB and b. BA, if A = 1 2 3 4 and B = a. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. AB = (Simplify your answers.) B. This matrix operation is not possible. b. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. BA = |(Simplify your answers.) O B. This matrix operation is not possible.

4 Find (if possible) a. AB and b. BA, if A = 1 2 3 4 and B = a. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. AB = (Simplify your answers.) B. This matrix operation is not possible. b. Select the correct choice below and, if necessary, fill in the answer box to complete your choice. O A. BA = |(Simplify your answers.) O B. This matrix operation is not possible.

Algebra and Trigonometry (MindTap Course List)

4th Edition

ISBN:9781305071742

Author:James Stewart, Lothar Redlin, Saleem Watson

Publisher:James Stewart, Lothar Redlin, Saleem Watson

Chapter11: Matrices And Determinants

Section11.2: The Algebra Of Matrices

Problem 2E

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Similar questions

A factory manufactures three products (doohickies, gizmos, and widgets) and ships them to two warehouses for storage. The number of units of each product shipped to each warehouse is given by the matrix A=[20015010075100125] (where aij is the number of units of product i sent to warehouse j and the products are taken in alphabetical order). The cost of shipping one unit of each product by truck is $1.50 per doohickey, $1.00 per gizmo, and $2.00 per widget. The corresponding unit costs to ship by train are $1.75, $1.50, and $1.00. Organize these costs into a matrix B and then use matrix multiplication to show how the factory can compare the cost of shipping its products to each of the two warehouses by truck and by train.
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In a previous section, we showed that matrix multiplication is not commutative, that is, ABBA in most cases. Can you explain why matrix multiplication is commutative for matrix inverses, that is, A1A=AA1 ?