4- For an AWGN channel, if SNR (signal to noise ratio) =14 and bandwidth -20kHz, then the channel capacity ---- bps 5- The efficiency of BSC (Binary Symmetric Channel) is 70 %, then the redundancy of the channel is---

Introductory Circuit Analysis (13th Edition)
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Publisher:Robert L. Boylestad
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-:Q3
Q3: fill the blank
1- The first row of A TSC (Ternary Symmetric Channel) is [0.8 0.1 0.2], then the
third row of this channel is --
2- A BSC (Binary Symmetric Channel) with probability of error =0.4, then p(x2/y1)
3- A binary symmetric channel with error probability of 0.1 and marginal entropy
P(yl) = 0.7, P(y2) =0.3. Find the efficiency
4- For an AWGN channel, if SNR (signal to noise ratio) =14 and bandwidth
-20kHz, then the channel capacity ---bps
5- The efficiency of BSC (Binary Symmetric Channel) is 70 %, then the
redundancy of the channel is---
6- The efficiency of BSC can be calculated as---
7- write the channel of TSC (Ternary Symmetric Channel) with Px1=0.5 , px2=0.1
px3=0.2 .
8- find the capacity if marginal entropy-0.57 with A binary symmetrie channel
with error probability of 0.7.
ث إضافة ملف
Transcribed Image Text:-:Q3 Q3: fill the blank 1- The first row of A TSC (Ternary Symmetric Channel) is [0.8 0.1 0.2], then the third row of this channel is -- 2- A BSC (Binary Symmetric Channel) with probability of error =0.4, then p(x2/y1) 3- A binary symmetric channel with error probability of 0.1 and marginal entropy P(yl) = 0.7, P(y2) =0.3. Find the efficiency 4- For an AWGN channel, if SNR (signal to noise ratio) =14 and bandwidth -20kHz, then the channel capacity ---bps 5- The efficiency of BSC (Binary Symmetric Channel) is 70 %, then the redundancy of the channel is--- 6- The efficiency of BSC can be calculated as--- 7- write the channel of TSC (Ternary Symmetric Channel) with Px1=0.5 , px2=0.1 px3=0.2 . 8- find the capacity if marginal entropy-0.57 with A binary symmetrie channel with error probability of 0.7. ث إضافة ملف
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