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(4) From the data given below calculate AGT200 and hence comment on the feasibility of use of hydrogen as a reductant for copper(I) oxide: Cu2 0(s) + H2(g) 2Cu(s) + H2 O(g) Standard enthalpy changes of formation: AH98 (Cu2 O(s)] = -164 kJ mol AH198 (H2 O(g)] = -242 kJ mol Heat capacities, C, in J K mol (assumed to remain constant in the range 298- 1200 K): Cu, O(s) 70.0 H2 (g) 29.0 Cu(s) 24.2 H2 O(g) 33.5 Standard entropies, ASe in J K-l mol¬! (assume that AS298 remains constant in the range 298-1200 K): Cu2 O(s) 94 H2(g) 131 Cu(s) 33 H2O(g) 188

(4) From the data given below calculate AGT200 and hence comment on the feasibility of use of hydrogen as a reductant for copper(I) oxide: Cu2 0(s) + H2(g) 2Cu(s) + H2 O(g) Standard enthalpy changes of formation: AH98 (Cu2 O(s)] = -164 kJ mol AH198 (H2 O(g)] = -242 kJ mol Heat capacities, C, in J K mol (assumed to remain constant in the range 298- 1200 K): Cu, O(s) 70.0 H2 (g) 29.0 Cu(s) 24.2 H2 O(g) 33.5 Standard entropies, ASe in J K-l mol¬! (assume that AS298 remains constant in the range 298-1200 K): Cu2 O(s) 94 H2(g) 131 Cu(s) 33 H2O(g) 188

Introduction to Chemical Engineering Thermodynamics
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
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(4) From the data given below calculate AGi200 and hence comment on the feasibility of use of hydrogen as a reductant for copper(I) oxide: Cu2 O(s) + H2(g) 2Cu(s) + H2 O(g) Standard enthalpy changes of formation: AH98 ( Cu2 O(s)] AH98 (H2 O(g)] -164 kJ mol = -242 kJ mol Heat capacities, C, in J K mol (assumed to remain constant in the range 298- 1200 K): Cu, O(s) 70.0 H2 (g) 29.0 Cu(s) 24.2 H2O(g) 33.5 Standard entropies, AS in J K-l mol- (assume that AS298 remains constant in the range 298-1200 K): Cu2 O(s) 94 H2(g) 131 Cu(s) 33 H2 O(g) 188 Canicaer
Transcribed Image Text:(4) From the data given below calculate AGi200 and hence comment on the feasibility of use of hydrogen as a reductant for copper(I) oxide: Cu2 O(s) + H2(g) 2Cu(s) + H2 O(g) Standard enthalpy changes of formation: AH98 ( Cu2 O(s)] AH98 (H2 O(g)] -164 kJ mol = -242 kJ mol Heat capacities, C, in J K mol (assumed to remain constant in the range 298- 1200 K): Cu, O(s) 70.0 H2 (g) 29.0 Cu(s) 24.2 H2O(g) 33.5 Standard entropies, AS in J K-l mol- (assume that AS298 remains constant in the range 298-1200 K): Cu2 O(s) 94 H2(g) 131 Cu(s) 33 H2 O(g) 188 Canicaer
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