4- I = 57 4x+1 dx

Q: Evaluate:

A:

Q: 1 -dx 3-4х

A:

Q: 1 )dx 4.

A: We will use substitution method to solve question 4.

Q: 3 Inx S- 2. xV In'x – 4 -dx

A: Consider the given integral ∫ln3xxln2x-4dx Use the substitution method to find the solution of the…

Q: | 2(x - 1)(x5 - 6x + 9)-5 dx

A:

Q: Exercises To Solve [No.5] dx OS (x-1) √X²2X-3 dx 3-2x-x²

A:

Q: 1 dx 4x 12 /-

A: Our Aim is to integrate ∫2314xdx -(i)

Q: Ул4 — dx 2x2 + 1 3,

A:

Q: 2. (cax-6)*dx

A:

Q: Exercises To Solve [No.5] ⒸS dx (x-1) √X²2X-3

A:

Q: sec2 (을) dx 23

A: The given integral is ∫sec24x2x3dx.

Q: (2²–4)* -dx (x-2)²

A: We have to find the given integral

Q: 3 + 2/5x-3 dx. Find 4x+1 - Vez

A:

Q: 5 -x° + 2x 3 dx .2 x +4

A: Consider ∫x5-x3+2xx2+4dx = ∫x5+4x3-5x3+2xx2+4dx= ∫x5+4x3-5x3-20x+2x+20xx2+4dx=…

Q: (а) (3x +5(5х -6) dx (b) 15х3 -10х? +15 dx 5x?

A:

Q: -4 6. |a + 3|dx – 1)³ydy -1

A:

Q: 44. (-x + 4x – 5) dx -2

A:

Q: Find 23x(10)* -' dx

A: The given integral is ∫23x10x-1dx

Q: (1+2 In æ)4 -dx

A: Indefinite Integration using substitution

Q: 6x + 7 -dx. (x +2)2

A:

Q: 2 ди ди + 2y ду ди du az .2 dx dx

A:

Q: | 2sin (x) dx = %3D

A: The answer is given below:

Q: 3 24- dx (3— 4x(х + 1)

A:

Q: dx 12 S. x-3)

A: 12. ∫451x-3dx

Q: Integrate: a+2– +2x²-1 dx

A:

Q: Solve using fragmentation of fractions 1 dX x(х — 1)?

A:

Q: 2х + 1 бх2 + 23х — 9 dx х3 + 2х2 — 3х Ja- 2)(x – 3)² dx

A:

Q: 2) dx -

A: We will solve the integration by the substitution, t = ex

Q: 1) dx 4. -3x + 2)

A:

Q: 8. f sec² (3x - 1) dx

A:

Q: (25х + 14) ег dx -

A: We solve this problem by help of integration by parts.

Q: integrate  (X^2-3)^2 dx;

A: To find the integral.

Q: integrate [7x ^ (- 2/3) + (x + 2) ^ 2] dx

A:

Q: sec(-3x + 5) dx

A: Solve the integral

Q: ii) Evaluate 3 -dx . Hence, solve et 2e* -dx . + +2

A:

Q: (2² –4)* -dx (x–2)²

A: First we simplify numerator with using appropriate identities then integrate

Q: ∫〖7(4x-1)^6 dx〗

A:

Q: 1 -dx V 6 + 4x – 2X

A: To evaluate: ∫16+4x-2x2dx

Q: 1— (Iпх)2 dx -

A:

Q: 5. 二 250e-0.5x dx

A:

Q: 4 dx V1- 25x2

A:

Q: 0 1 S -8 (2x-1)3 -dx

A: ∫-∞0 12x-13dx

Q: (2x-3)4 dx 10

A: Given:The integral is

Q: Find + 3) (т - 4)dx

A: The given integral can be solved by simplifying the equation

Q: How to solve dx = 2dy = -2dz.

A:

Q: 9. -dx 5 Vx – 5

A:

Q: S,12x – 3|dx 3. -

A: ∫04|2x - 3|dx In the limit 0 to 4, we need to open the modulus sign: fx = 2x - 3 = 0   ⇒ x = 32  So,…

Q: (13 -3x + 8 ) dx

A:

Q: 2) dx 4. - |

A: We can use method of substitution in order to solve the problem problem.

Equations and Inequations

Equations and inequalities describe the relationship between two mathematical expressions.

Linear Functions

A linear function can just be a constant, or it can be the constant multiplied with the variable like x or y. If the variables are of the form, x2, x1/2 or y2 it is not linear. The exponent over the variables should always be 1.