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- What is ΔSsurr for a reaction at 19 °C with ΔHsys = -7.3 kJ mol-1 ? Express your answer in J mol-1 K-1 to at least two significant figures.The kinetics of hydrolysis of acetylsalicylic acid (aspirin) under certain conditions of temperature, pH, type of buffer and strength ionic, can be followed by multicomponent spectrophotometry. When performing a calculation of optical constants, the following data were obtained: Solution C. mg/100 mL A in λ (276nm) A in λ (290nm) Ac. acetylsalicylic ( AAS) 0.202 0.102 0.031 Ac. salicylic (AS) 0.198 0.158 0.101 Reaction: AAS + H2O → AS + CH3COOH In a kinetic study, after a certain time, 1 mL of the solution was taken from the reactor and diluted to 10 mL with water. distilled. Then when proceeding to the spectrophotometric measurement, the last solution presented the absorbances of 0.244 and 0.102 for the lengths of 276 and 290 nm respectively. What are the concentrations of ASA and AS in mg/L, at that instant in the reactor? Note: Acetic acid does not absorb at either wavelength.subunit G.H.I please
- The binding of Mg2+ to glycolate anion, (HO-CH2-COO-) proceeds by thisequilibrium:Mg2+ + HO-CH2-COO- ->Mg2+(HO-CH2-COO-) a) Write the expression for Keq for this reversible reaction. b) If you begin with 5 mM Mg2+ and 0.1 mM HO-CH2-COO-, and with a value of Keq = 103 M-1, calculate the concentrations of Mg2+ , HO-CH2-COO-, and Mg2+(HO-CH2-COO-) at equilibrium.An enzyme-catalyzed reaction is studied in the absence and presence of an inhibitor and the following data was obtained. [S] in mmoles/L Velocity in mmoles/L/min-1 No inhibitor With inhibitor 1.25 1.72 0.98 1.67 2.04 1.17 2.50 2.63 1.47 5.00 3.33 1.96 10.00 4.17 2.38 Calculate the Km of the enzyme in the reaction without inhibitor ________________________ Km’ of the enzyme in the reaction with inhibitor ________________________ Vmax of the uninhibited reaction ________________________ Vmax’ of the inhibited reaction ________________________Which of the following is a spontaneous reaction.? a. Rxn with ΔH =- 10Kj/mol ΔS= -5J/mol T= 300K b. NaCl +H20 -> NaOH + HCl 25C c. H20(l) -> H2O(s) Temp: 25C d. Dissolution of 100g of solid sugar in 100 mL ice tea. Consider following reaction: HgO (s) -> Hg(l) + ½ O2 (g) Delta H = +90.7 kj/mol. What quantity of heat in kj/mol is required to produce one mole HgO? Write your answer without units. Given the following data 2ClF(g) + O2(g) --> Cl2O(g) + F2O (g) Delta H= 167.4 kJ I 2ClF3(g) + 2O2(g) --> Cl2O(g) + 3F2 O (g) Delta H= 341.4 kJ II 2 F2(g) + O2(g) ---> 2F2O (g) Delta H= -43.4 kJ III Calculate the delta H in kJ for below reaction: ClF(g) + F2(g) ---> ClF3(g)
- Ff.24. With explanation ......For the reaction 2Na (g) Na2 (g) the following values of K have been determined (C. T. Ewinget al., J. Chem. Phys. 1967, 71, 473):T (K) K900 1.321000 0.471100 0.211200 0.10From these data, estimate rxnH° for the reaction.The following lifetimes were measured for the chloride quenching of quinine sulfate given in Example 15-1.The fluorescence intensities are given in the example. (a) Plot fluorescence intensity versus [Cl-]. (b) Plot the ratio of intensity to lifetime, F- versus [Cl-]. (c) Develop a normalization factor to correct the measured fluorescence intensity to that of the solution without quencher. (d) Plot on the same graph Fversus [Cl-] and Fcorr versus (CI-].
- Please determine Hvap using these: P2- 3.7kpaP1- 19.2kpa T2-276.65KT1-330.15KA research group discovers a new version of happyase, which they call happyase*, that catalyzes the chemical reaction The researchers begin to characterize the enzyme. a)In the first experiment, with [Et] at 4 nM, they find that the Vmax is 1.6 μM s-1. Based on this experiment, what is the kcat for happyase*? (Include appropriate units.) b)In another experiment, with [Et] at 1 nM and [HAPPY] at 30 μM, the researchers find that V0300 nM s-1. What is the measured Km of happyase* for its substrate HAPPY? (Include appropriate units.) c)Further research shows that the purified happyase* used in the first two experiments wasactually contaminated with a reversible inhibitor called ANGER. When ANGER is carefully removed from the happyase* preparation, and the two experiments repeated, the measured Vmax in (a) is increased to 4.8 μM s-1, and the measured Km in (b) is now 15 μM. For the inhibitor ANGER, calculate the values of αand α’.The vapor-liquid reactive equilibria for ethyl lactate synthesis follows the expressionlog K = 7.893 – (2.4312 x 103)K/Tbetween 83.12 °C and 101.54 °C. What are the ΔH°rxn, ΔG°rxn, and ΔS°rxn at 85 °C?Ind. Eng. Chem. Res. 2008, 47, 5, 1453–1463