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4) The force of attraction between a positive charge Q and a negative charge q (in magnitude) is kQq F = r2 Where r is the distance of separation in meters. Use the following constants: m² 2 k = 8.99 x 109 N- Q = +3.21 μC, q = -2.11 μC C2 Calculate the work done by separating the charges from r = 2.00 to r = 5.00 cm.

4) The force of attraction between a positive charge Q and a negative charge q (in magnitude) is kQq F = r2 Where r is the distance of separation in meters. Use the following constants: m² 2 k = 8.99 x 109 N- Q = +3.21 μC, q = -2.11 μC C2 Calculate the work done by separating the charges from r = 2.00 to r = 5.00 cm.

Mathematics For Machine Technology
Mathematics For Machine Technology
8th Edition
ISBN:9781337798310
Author:Peterson, John.
Publisher:Peterson, John.
Chapter61: Areas Of Circles, Sectors, And Segments
Section: Chapter Questions
Problem 23A: A force of 62,125 pounds pulls on a steel rod that has a diameter of 1800 inches. Find the force...
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4) The force of attraction between a positive charge Q and a negative charge q (in magnitude) is kQq F = r2 Where r is the distance of separation in meters. Use the following constants: m² 2 k = 8.99 x 109 N- Q = +3.21 μC, q = -2.11 μC C2 Calculate the work done by separating the charges from r = 2.00 to r = 5.00 cm.
Transcribed Image Text:4) The force of attraction between a positive charge Q and a negative charge q (in magnitude) is kQq F = r2 Where r is the distance of separation in meters. Use the following constants: m² 2 k = 8.99 x 109 N- Q = +3.21 μC, q = -2.11 μC C2 Calculate the work done by separating the charges from r = 2.00 to r = 5.00 cm.
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