4. A cherry pie with a temperature of 120°C was placed on a table to cool in a room of constant temperature 25°C. After 5 minutes, the temperature of the pie had dropped to 89°C. How long, after the pie was placed, would the temperature be 65°C? Use Newton's Law of Cooling : = -k(T – T,). dt

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A:

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A: As we know that; If F→=F1i+F2j+F3k then ∇×F=ijk∂∂x∂∂y∂∂zF1F2F3 Given: Fx,y,z=5xy j+10xyz k

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A: Please refer to the image below

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A: Given problem:-

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A: Please see the answer below.

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A:

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A: Given that,   Using integration by part

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A: This question can be solved using the concept of trigonometry.

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A:

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A: Let's find.

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A: Differentiation

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A: On solving this we will get:- Option (A) is correct.