4. a) Sketch the graphs ofy=f(x) = -2(x – 3)2 + 2 and y=g(x)= 4x – 10 on the same set of axes. b) Calculate the points of intersection of the two graphs. c) Write down the domain and range of f and g.

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A: To sketch the graph

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Q: 2. Sketch the graph of the function (a) f(x,y) = /x2 + y²

A: See the attachment

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Q: use the graph of y=f(x) to graph g(x)=2f(x-1)+1 given the coordiantes (-4,0) (-2,-2) (0,0) (2,2)…

A: xf(x)-40-2-2002240   let us take x = -3, -1, 1, 3, 5 x   x-1      f(x-1)     g(x) = 2f(x-1)…

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Q: question 4

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Q: 1. How does the graph of f (x) = vVx – 2 differ from the graph of y = Vx+ 3 ?]

A: The value of sqrt(x-2) is differ from the value of sqrt(x+3).

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A: It is given that, f(x)=|x|+1   and if y=f(2x), then the function will be, y=f(2x)⇒y=|2x|+1⇒y=2|x|+1…

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A: That is,

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A: Given that f(12) = 4  We will use this fact to find the answer as shown below

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A: Please refer the attached image for complete solution.THANK YOU.

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