4. After 3 days a sample of Radon-222 has decayed to 58% of its original amount.(a)What is the half-life of Radon-222?t = 3 and m(3) = 0.58 nFormula: m(t)= m, e¯™В то> 0.58 = e-3r→ - 3r = In 0.58 = r= 0.1816The half-life: h =-In 2= 3.8174 daysr(b)How long will it take the sample to decay to 20% of its original amount?m(t)= 0.2 m, = 0.2 = e"- In 0.2t =0.1816rt = – In 0.2= 8.8625 days

Answered: Image /qna-images/answer/d2071409-6afd-491f-a679-e98ed228e5f5.jpg

4. After 3 days a sample of Radon-222 has decayed to 58% of its original amount. (a) What is the half-life of Radon-222? t = 3 and m(3)= 0.58 m, Formula: m(t)= m, e" In 2 > 0.58 = e-3r > - 3r = ln 0.58 > r= 0.1816 The half-life: h = = 3.8174 days (b) How long will it take the sample to decay to 20% of its original amount? m(t)= 0.2 m, > 0.2 = e" - In 0.2 t = 0.1816 rt = - In 0.2 = 8.8625 days

4. After 3 days a sample of Radon-222 has decayed to 58% of its original amount. (a) What is the half-life of Radon-222? t = 3 and m(3)= 0.58 m, Formula: m(t)= m, e" In 2 > 0.58 = e-3r > - 3r = ln 0.58 > r= 0.1816 The half-life: h = = 3.8174 days (b) How long will it take the sample to decay to 20% of its original amount? m(t)= 0.2 m, > 0.2 = e" - In 0.2 t = 0.1816 rt = - In 0.2 = 8.8625 days

Algebra & Trigonometry with Analytic Geometry

13th Edition

ISBN:9781133382119

Author:Swokowski

Publisher:Swokowski

Chapter5: Inverse, Exponential, And Logarithmic Functions

Section: Chapter Questions

Problem 18T

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