+ea(t)RawwwJ₁ = 4 kg-m²N₁ = 50D₁N₂= 150,D₂ = 36 N-m-s/rad8 N-m-s/rad½ = 36 kg-m²³OL(1)T (N-m)15050 V100@ (rad/s)4. (Draw the equivalent electrical network of the rotational system described in Problem 2.

The given figure is shown below. The torque vs speed curve is shown below. We need to draw the…

4. ea(t) Ra www J₁ = 4 kg-m² N₂ = 150 D₂ = 36 N-m-s/rad N₁ = 50 D₁ = 8 N-m-s/rad OL(1) 0¹/2₂ 5 kg-m² = 36 T (N-m) 150 50 V 100 @ (rad/s) Draw the equivalent electrical network of the rotational system described in Problem 2.

4. ea(t) Ra www J₁ = 4 kg-m² N₂ = 150 D₂ = 36 N-m-s/rad N₁ = 50 D₁ = 8 N-m-s/rad OL(1) 0¹/2₂ 5 kg-m² = 36 T (N-m) 150 50 V 100 @ (rad/s) Draw the equivalent electrical network of the rotational system described in Problem 2.

Introductory Circuit Analysis (13th Edition)

13th Edition

ISBN:9780133923605

Author:Robert L. Boylestad

Publisher:Robert L. Boylestad

Chapter1: Introduction

Section: Chapter Questions

Problem 1P: Visit your local library (at school or home) and describe the extent to which it provides literature...

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Question

+
ea(t)
Ra
www
J₁ = 4 kg-m²
N₁ = 50
D₁
N₂= 150,
D₂ = 36 N-m-s/rad
8 N-m-s/rad
½ = 36 kg-m²³
OL(1)
T (N-m)
150
50 V
100
@ (rad/s)
4. (Draw the equivalent electrical network of the rotational system described in Problem 2.

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