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4. Given the following information: (Enthalpy of Formation) AHF°(NO2, gas) = 33.18 kJ/mol AHF°(H2O, liquid) = -285.5 kJ/mol AHF°(HNO3, aqueous) = -207.36 kJ/mol AHF°(NO, gas) = 90.25 kJ/mol %3D Calculate the AH° for the reaction below: 3 NO2(g) + H2O(1) -> 2 HNO3(aq) + NO(g),

4. Given the following information: (Enthalpy of Formation) AHF°(NO2, gas) = 33.18 kJ/mol AHF°(H2O, liquid) = -285.5 kJ/mol AHF°(HNO3, aqueous) = -207.36 kJ/mol AHF°(NO, gas) = 90.25 kJ/mol %3D Calculate the AH° for the reaction below: 3 NO2(g) + H2O(1) -> 2 HNO3(aq) + NO(g),

Chemistry: Principles and Reactions
Chemistry: Principles and Reactions
8th Edition
ISBN:9781305079373
Author:William L. Masterton, Cecile N. Hurley
Publisher:William L. Masterton, Cecile N. Hurley
Chapter8: Thermochemistry
Section: Chapter Questions
Problem 39QAP: Given 2Al2O3(s)4Al(s)+3O2(g)H=3351.4kJ (a) What is the heat of formation of aluminum oxide? (b) What...
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4. Given the following information: (Enthalpy of Formation) AHF°(NO2, gas) = 33.18 kJ/mol AHF°(H2O, liquid) = -285.5 kJ/mol AHF°(HNO3, aqueous) = -207.36 kJ/mol AHF°(NO, gas) = 90.25 kJ/mol %D Calculate the AH° for the reaction below: 3 NO2(g) + H2O(1) -> 2 HNO3(aq) + NO(g),
Transcribed Image Text:4. Given the following information: (Enthalpy of Formation) AHF°(NO2, gas) = 33.18 kJ/mol AHF°(H2O, liquid) = -285.5 kJ/mol AHF°(HNO3, aqueous) = -207.36 kJ/mol AHF°(NO, gas) = 90.25 kJ/mol %D Calculate the AH° for the reaction below: 3 NO2(g) + H2O(1) -> 2 HNO3(aq) + NO(g),
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