4. If a lion lies stretched out over the entire length of the branch in question 3, exerting a constant force of F = 500 N / m over the entire length of the l.5 m branch. It is given that I = 1 × 10-6 m* and E = 2× 10° Nm¯². The boundary conditions are y(0) = 0, y'(0) = 0 , y'"(0) = M and y''(0) = –2M. Use your notes to model the fourth order differential equation suited to this application. Present you differential equation with y''' subject of the equation. Use direct integration and solve this equation in terms of M. Determine the deflection (in terms of M ) at x = 1.5 m. Do not use Matlab as its solution will not be identifiable in the solution %3D entry.

4. If a lion lies stretched out over the entire length of the branch in question 3, exerting a constant force of F = 500 N / m over the entire length of the l.5 m branch. It is given that I = 1 × 10-6 m* and E = 2× 10° Nm¯². The boundary conditions are y(0) = 0, y'(0) = 0 , y'"(0) = M and y''(0) = –2M. Use your notes to model the fourth order differential equation suited to this application. Present you differential equation with y''' subject of the equation. Use direct integration and solve this equation in terms of M. Determine the deflection (in terms of M ) at x = 1.5 m. Do not use Matlab as its solution will not be identifiable in the solution %3D entry.

Elements Of Electromagnetics

7th Edition

ISBN:9780190698614

Author:Sadiku, Matthew N. O.

Publisher:Sadiku, Matthew N. O.

ChapterMA: Math Assessment

Section: Chapter Questions

Problem 1.1MA

See similar textbooks

Similar questions

4. A bead of mass 0.1kg is bound to a linear track which connects the points (1,2,3) and (-1,2,4). The bead moves in response to a force field F = (xy²z, x,z²). Find the work done by the force field in moving the particle using .t₁ dr dt WD = - to F dt
A bead of mass 0.1kg is bound to a linear track which connects the points (1,2,3) and (-1,2,4). The bead moves in response to a force field F = (xy²z, x, z²). Find the work done by the force field in moving the particle using t₁ dr WD = dt F I dt
the non-homogeneous equation y” – 2y’ = t + dt, then determine this solution
Answer for the 1st part of the problem. magnitude of force A = 74 N direction of force A = 25o north of west second force = P direction of force P = α south of west arrow_forward The resultant of two forces is horizontal , it means that the y component of resultant = 0 Ry = ASin(25o) - PSin(α) 0 = (74×0.42) - PSin(α) PSin(α) = 31.08 NFor, the smallest force P , the value of Sinα must be maximum which is 1 when the value of αis 90 degree Thus, P×Sin(90o) = 31.08 N P = 31.08 N The magnitude of smallest force P = 31.08 N the direction of force P = 90 degree south of west = along - y axis= arrow pointing vertically downw
What is the horizontal component of F1 = 60N at 220°
A force P in the xy-plane acts on the triangular plate. The moments of P about points O, A, and B are MO =80 N · m counterclockwise, MA =200 N.m clockwise, and MB =0 Determine the Py
FY Find the two components of the force (200 N) if a= 60 degrees, as :shown in the figure below F= 200 N α= 60 FX (FX= 100 N) AND (FY= 73.2N) O (FX= 173.2 N) AND (FY= 100N) O (FX= 100 N) AND (FY= 173.2N) O
The top of a ladder weighing 20 kg and 6m long rests against a vertical wall and the foot of the ladder on a horizontal floor. For the wall, if = 0.15, and for the floor, f = 0.2 0. How far up the ladder can a man weighing 60 kg go before the ladder begins to slip? Take moment at A to find the value of Х. * 60 Kg - NB 0.15 kg 20 kg 60° A 0.2 NA NA
The top of a ladder weighing 20 kg and 6m long rests against a vertical wall and the foot of the ladder on a horizontal floor. For the wall, if = 0.15, and for the floor, f = 0.2 O. How far up the ladder can a man weighing 60 kg go before the ladder begins to slip? Take moment at A to find the value of Х. * 60 Kg B NB 0.15 kg X 20 kg 60° A 0.2 NA NA 6m
* when we have smooth surface at the contact to the body, we will have one tangent force to the body True O False O
A force P in the xy-plane acts on the triangular plate. The moments of P about points O, A, and B are MO =80 N · m counterclockwise, MA =200 N.m clockwise, and MB =0 Determine the Px.
ENGINEERING MECHANICS: STATICS (J.L.MERIAM) 2/4: The line of action of the 9.6-kN force F runs through the points A and B as shown in the figure. Determine the x and y scalar components of F. Ans. y, mm B (300, 100) X, mm F 9.6 kN A(-150,-200) 2/5: A cable stretched between the fixed sunnorts A and Bis under a tencien Tef 000 NL