4. If the thickness and width of the dog bone for PP are 0.12" and 0.5", respectively, and the initial length is 4.5": a. Calculate the yield point (Ib), yield stress (psi) and elongation at yield b. Calculate the break point (lb), stress at break (psi) c. Calculate elongation at break (%) d. Calculate Modulus of Elasticity (psi)

Mechanics of Materials (MindTap Course List)
9th Edition
ISBN:9781337093347
Author:Barry J. Goodno, James M. Gere
Publisher:Barry J. Goodno, James M. Gere
Chapter1: Tension, Compression, And Shear
Section: Chapter Questions
Problem 1.6.5P: An aluminum bar has length L = 6 ft and diameter d = 1.375 in. The stress-strain curse for the...
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250
3501
225
Yield: 307 lb, 0.1375 in
Gap: 4.5"
Width: 0.5"
300
Thickness: 0.125"
200
Area: 0.5 x 0.125 in? = 0.0625 in
250
YIELD POINT
L
D
Yield Force: 307 1b
175
Yield Stress: 307/0.0625 psi =
200
4912 psi
% Elongation at vield:
(0.1375/4.5) x 100% = 3.05%
200 lb, 0.075 in
Ibf
150
150
BREAKING POoINT
Break: 130 lb, 0.25 in
Breaking Force: 130 lb
Breaking Stress: 130/0.0625 psi=
2080 psi
A
100
125
% elongation at break
(0.25/4.5) x 100% = 5.5%
50
100
POSITION, in
250
500
.750
1.00
1.25
1.
Ibf
75
TENSILE MODULUS CALCULATIONS:
In principal, tensile modulus is the SLOPE of force vs. distance graph. You choose any random
force, calculate the stress and distance at that point. Then calculate the stress and elongation.
50
o Choose the point at 200 lb and 0.075 in. This is a random choice
•
o Stress at 200 1b is 200/0.0625 psi = 3200 psi
O Elongation at 0.075 in is (0.075/4.5) x 100% = 1.66
o Tensile Modulus = 3200/1.66 psi = 1920 psi
25
POSITION, in
.250
.500
.750
1.00
1.25
1.50
1.75
2.00
2.25
2.50
Transcribed Image Text:250 3501 225 Yield: 307 lb, 0.1375 in Gap: 4.5" Width: 0.5" 300 Thickness: 0.125" 200 Area: 0.5 x 0.125 in? = 0.0625 in 250 YIELD POINT L D Yield Force: 307 1b 175 Yield Stress: 307/0.0625 psi = 200 4912 psi % Elongation at vield: (0.1375/4.5) x 100% = 3.05% 200 lb, 0.075 in Ibf 150 150 BREAKING POoINT Break: 130 lb, 0.25 in Breaking Force: 130 lb Breaking Stress: 130/0.0625 psi= 2080 psi A 100 125 % elongation at break (0.25/4.5) x 100% = 5.5% 50 100 POSITION, in 250 500 .750 1.00 1.25 1. Ibf 75 TENSILE MODULUS CALCULATIONS: In principal, tensile modulus is the SLOPE of force vs. distance graph. You choose any random force, calculate the stress and distance at that point. Then calculate the stress and elongation. 50 o Choose the point at 200 lb and 0.075 in. This is a random choice • o Stress at 200 1b is 200/0.0625 psi = 3200 psi O Elongation at 0.075 in is (0.075/4.5) x 100% = 1.66 o Tensile Modulus = 3200/1.66 psi = 1920 psi 25 POSITION, in .250 .500 .750 1.00 1.25 1.50 1.75 2.00 2.25 2.50
4. If the thickness and width of the dog bone for PP are 0.12" and 0.5",
respectively, and the initial length is 4.5":
a. Calculate the yield point (lb), yield stress (psi) and elongation at yield
b. Calculate the break point (lb), stress at break (psi)
c. Calculate elongation at break (%)
d. Calculate Modulus of Elasticity (psi)
Transcribed Image Text:4. If the thickness and width of the dog bone for PP are 0.12" and 0.5", respectively, and the initial length is 4.5": a. Calculate the yield point (lb), yield stress (psi) and elongation at yield b. Calculate the break point (lb), stress at break (psi) c. Calculate elongation at break (%) d. Calculate Modulus of Elasticity (psi)
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