4. Use the product rule twice to prove that if f, g,h are differentiable, then (fgh)' = f'gh + fg'h + f gh'. Then taking f = g = h, show that: f (æ)]³ = 3[f(x)]J²f"(x) Then, use this result you just showed to differentiate y = (x² + 3x3 + 17x + 82)3

College Algebra
1st Edition
ISBN:9781938168383
Author:Jay Abramson
Publisher:Jay Abramson
Chapter3: Functions
Section3.3: Rates Of Change And Behavior Of Graphs
Problem 2SE: If a functionfis increasing on (a,b) and decreasing on (b,c) , then what can be said about the local...
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4. Use the product rule twice to prove that if f, g, h are differentiable, then (fgh)' =
f'gh + fg'h + fgh'. Then taking f = g = h, show that:
d
[f(x)]³ = 3[f(x)]²f'(x)
dx
Then, use this result you just showed to differentiate y =
(x* + 3.x3 + 17x + 82)3
Transcribed Image Text:4. Use the product rule twice to prove that if f, g, h are differentiable, then (fgh)' = f'gh + fg'h + fgh'. Then taking f = g = h, show that: d [f(x)]³ = 3[f(x)]²f'(x) dx Then, use this result you just showed to differentiate y = (x* + 3.x3 + 17x + 82)3
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