answer 4 5 6 handwritten DATA COLLECTION SHEETThe Normal Distribution ActivitySurvey Link: https://forms.gle/7XW7ÉEHPB592HYWD7For Data Set 1Mean =8.70Variance =4,6423Standard Deviation =2.1546Data Set 1Data Set 2Data Set 3Number of pets atDaily screen time (inhours) of 20 selectedstudents from Grade1. Sketch the first bell curve by showing the mean and standard deviation.Shoe size (in inches) of20 selected studentshome of 20 selectedStudentStudentStudentstudents from Grade112 petsfrom Grade 11118.75 inches10 hours11110 hours9 pets9 inches2311 hours3O pets38.5 inches6 hours45 pets48 inches510 hours52 pets59 inches10 hours1 pet9.5 inches2. What is the data value (raw score) associated with a standard score of 1.1? Determine thepercentage less than this score. Draw the curve and show your complete solution.6.66.9 hours4 pets7 inches77787 hours8.1 pet88.5 inches7 hours3 pets8.5 inches9.92. 3101 : X-t.10H.. THAN aer105 hours102 pets107.5 inches117 hours113 pets116 inchesO LI125 hours122 pets128 inches1310 hours131 pet138 inchesThe percentage that is less than the raw score of 11.0701 hours is 84.38%.12 hoursO pets9 inches3. What is the data value (raw score) associated with a standard score of -0.09? Determine thepercentage greater than this score. Draw the curve and show your complete solution.1414146 hours1 pet9 inches1515151611 hours16O pets168.5 inches-0.09-x-t.K1.15 461710 hours17O pets179 inches0. tisg188 hours181 pet188 inches199 hours191 pet197 inches2011 hours202 pets209.75 inches-0.4 0The percentage that is greater than the raw score of 8.5061 hours is 81.59%. 4. What is the range (sxs_) of the data values that would allow 55% of the data to fallwithin the mean observing symmetry? Draw the curve and show your complete solution.The Normal Distribution ActivityFor Data Set 2A. 4. 110 ;..16A 0. 150 1G..500Mean =2.000Variance =4.5263Standard Deviation =2.1275THE RANGE OF THE DATA UALUES7. Sketch the second bell curve by showing the mean and standard deviation.UHEN -0,GTO PALL n E MERN ORsrenNE0.16 x-t.. G A-t.t0hart1.6 315 : - t.10** 10. 945- 6SIS x-.1011.0025The range of data values that will allow 55% of the data to fall within the mean of symmetry is7.0625 and 10.33755. What is the variance of this data set?g? = (2.1546)?g? = 4.6423Given that the standard deviation is 2.1546 and it is the square root of the variance,8. What is the data value (raw score) associated with a standard score of 2.08? Determine thepercentage greater than this score. Draw the curve and show your complete solution.the value of the variance is 4.6423.6. Are there any outliers with this data set? (Outliers refer to data points that lie beyond 3standard deviation from the mean).2.0r- X- 12.1215Aocecior 0. versA1.0. .r .There are no outliers with this data set since all values in the data set do not go beyondthe three standard deviations from the mean.4.4151 X-*. G. V252r.12 o cereee T e eer2.09The percentage that is greater than the raw score of 6.4252 is 98.12%.9. What is the data value (raw score) associated with a standard score of -1.3? Determine thepercentage less than this score. Draw the curve and show your complete solution.-1.3.-12.1245Aze -1.3 = 0.5+ D. v032- 0.9032*. -0. 16590. 81, Lert HAN RAW SCoet1.3 0The percentage that is less than the raw score of -0.7658 is 90.32%.

Question

Accepted Answer

Given that, 
Mean is μ=8.70
Standard deviation σ=2.1546